Câu trả lời:
a) \(\sqrt{x}\)=3 ( ĐKXĐ: x\(\ge\)3)
<=> (\(\sqrt{x}\))2=32
<=>x=9
Vậy x=9
b)\(\sqrt{x}=\sqrt{5}\) ( ĐKXĐ : x\(\ge\)0)
<=>\(\left(\sqrt{x}\right)^2=\left(\sqrt{5}\right)^2\)
<=> x=5
Vậy x=5
c) \(\sqrt{x}=0\) (ĐKXĐ : x\(\ge\)0)
<=> \(\left(\sqrt{x}\right)^2=0^2\)
<=> x=0
Vậy x=0
d) \(\sqrt{x}=-2\) ( ĐKXĐ : x\(\ge\)0 )
<=>\(\left(\sqrt{x}\right)^2=\left(-2\right)^2\)
<=> x=4
Vậy x=4