Câu trả lời:
2KClO3→2KCl+3O22KClO3→2KCl+3O2
2KMnO4→K2MnO4+MnO2+O22KMnO4→K2MnO4+MnO2+O2
Ta có:
nKClO3=a122,5=nKCl→mKCl=a122,5.74,5=74,5a122,5nKClO3=a122,5=nKCl→mKCl=a122,5.74,5=74,5a122,5
nKMnO4=b158→nK2MnO4=nMnO2=12nKMnO4=b316→mK2MnO4+nMnO2=b316.(39.2+55+16.4+55+16.2)=71b79=74,5a122,5→ab=1,47778nKMnO4=b158→nK2MnO4=nMnO2=12nKMnO4=b316→mK2MnO4+nMnO2=b316.(39.2+55+16.4+55+16.2)=71b79=74,5a122,5→ab=1,47778
Ta có:
nO2 trong KClO3=32.nKClO3=32.a122,5;nO2 trong KMnO4=12nKMnO4=b316nO2 trong KClO3=32.nKClO3=32.a122,5;nO2 trong KMnO4=12nKMnO4=b316
Vì % số mol=% thể tích
→VO2 KClO3VO2KMnO4=32.a122,5b316=6,879