\(\begin{aligned} &\left(\frac{3}{4}-2 x\right)\left(-\frac{3}{5}+\frac{2}{-61}-\frac{17}{51}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\ &2 x)\left(-\frac{3}{5}-\frac{2}{61}-\frac{1}{3}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\ &2 x)\left(-\frac{549}{915}-\frac{335}{915}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\ &2 x)\left(-\frac{884}{915}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-2 x\right) \leq 0 \Leftrightarrow x \geq \frac{3}{8} \end{aligned}\)

\(\begin{aligned} &\left(\frac{3}{4}-2 x\right)\left(-\frac{3}{5}+\frac{2}{-61}-\frac{17}{51}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\ &\text { 2x })\left(-\frac{3}{5}-\frac{2}{61}-\frac{1}{3}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\ &\text { 2x) }\left(-\frac{549}{915}-\frac{335}{915}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\ &2 x)\left(-\frac{884}{915}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-2 x\right) \leq 0 \Leftrightarrow x \geq \frac{3}{8} \end{aligned}\)

Vậy \(x \geq \frac{3}{8}\)

\begin{aligned}
&\left(\frac{3}{4}-2 x\right)\left(-\frac{3}{5}+\frac{2}{-61}-\frac{17}{51}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\
&\text { 2x })\left(-\frac{3}{5}-\frac{2}{61}-\frac{1}{3}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\
&\text { 2x) }\left(-\frac{549}{915}-\frac{335}{915}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-\right. \\
&2 x)\left(-\frac{884}{915}\right) \geq 0 \Leftrightarrow\left(\frac{3}{4}-2 x\right) \leq 0 \Leftrightarrow x \geq \frac{3}{8}
\end{aligned}

Bài này bạn làm sai rồi nhé!