Câu trả lời:
Có: \(\left|x-y\right|\ge0\)
\(\left|y+\frac{9}{25}\right|\ge0\)
Theo bài ra: \(\left|x-y\right|+\left|y+\frac{9}{25}\right|=0\)
\(\)\(\Rightarrow\hept{\begin{cases}\left|x-y\right|=0\\\left|x+\frac{9}{25}\right|=0\end{cases}}\Rightarrow\hept{\begin{cases}y=x\\x=-\frac{9}{25}\end{cases}}\Rightarrow\hept{\begin{cases}y=-\frac{9}{25}\\x=-\frac{9}{25}\end{cases}}\)
Vậy: \(x=y=-\frac{9}{25}\)