\(A=3^1+3^2+...+3^{2006}\)

\(3A=3^2+3^3+...+3^{2007}\)

\(3A-A=\left(3^2+3^3+...+3^{2007}\right)-\left(3+3^2+...+3^{2006}\right)\)

\(2A=3^{2007}-3\)

=> 2a +3=3²⁰⁰⁷ - 3 + 3 = 3²⁰⁰⁷ = 3^x

=> x = 2007

Help Me......KKK

After (come-came-to come-coming) home, Tom reads the morning newspaper.

Thank you so much :333

21.We go to shool in order (to prepare-prepared-preparing-prepare) our future.

22.He refused (go-to go-going-goes) to the dentist.

23.We suggest (go-going-to go-went on a picnic.

Thank you so much....<3