a) \(\left(x+1\right)^4-\left(x-1\right)^4=\left[\left(x+1\right)^2\right]^2-\left[\left(x-1\right)^2\right]^2\)

\(=\left[\left(x+1\right)^2-\left(x-1\right)^2\right].\left[\left(x+1\right)^2+\left(x-1\right)^2\right]\)

\(=\left(x+1-x+1\right)\left(x+1+x-1\right)\left(x^2+2x+1+x^2-2x+1\right)\)

\(=2.2x.\left(2x^2+2\right)=8x\left(x^2+1\right)\)

b) \(\left(x^2-25\right)^2-4\left(x+5\right)^2=\left[\left(x-5\right)\left(x+5\right)\right]^2-4\left(x+5\right)^2\)

\(=\left(x+5\right)^2\left[\left(x-5\right)^2-4\right]=\left(x+5\right)^2\left(x^2-10x+25-4\right)=\left(x+5\right)^2\left(x^2-10+21\right)\)

\(=\left(x+5\right)^2\left(x-3\right)\left(x-7\right)\)

9 . 8 . 5 . 3 - 1080

=  ( 9 . 3) . ( 8 . 5 ) - 1080

= 27 . 40 - 1080

= 1080 - 1080

= 0

ủng hộ mk nhé !!! ^-^

35 x 2 = 70

ủng hộ mk nhé !!!! ^-^

\(a,2\sqrt{x}+\frac{1}{2}\sqrt{x}+\frac{7}{2}\sqrt{x}=6 \Leftrightarrow\sqrt{x}\left(2+\frac{1}{2}+\frac{7}{2}\right)=6\Leftrightarrow6\sqrt{x}=6\Leftrightarrow\sqrt{x}=1\Leftrightarrow x=1\)ĐKXĐ: x \(\ge\) 0

b, ĐKXĐ: x \(\ge\) \(\frac{7}{3}\)

3x - 7 + \(\sqrt{3x-7}\)=0

\(\Leftrightarrow\) (\(\sqrt{3x-7}\))(\(\sqrt{3x-7}\)+1)=0

\(\Leftrightarrow\) \(\left[{}\begin{matrix}\sqrt{3x-7}=0\\\sqrt{3x-6=0}\end{matrix}\right.\)\(\Leftrightarrow\) \(\left[{}\begin{matrix}x=\frac{7}{3}\\x=2\end{matrix}\right.\)(Tm)

1/2-1/3=1/6 suy ra tổng trên = -43/101

12x12x12x12x12=248 832

4x4x4x4x4x4x4x4= 65 536

Mong các bạn ủng hộ mk nhaaaa Ai đi qua xin để lại 1 k thuiii ạ

Làm ơn hãy k mk nhé @@@ Pờ lít đó ####

Chúc các bạn học giỏi như củ tỏi haaaaaa <3 ^^ <3

20 - 15 = 5

 minh la nguoi dau tien day