\(\frac{x^2}{\sqrt{3x-2}}-\frac{3x-2}{\sqrt{3x-2}}=\frac{\left(\sqrt{3x-2}\right)\left(1-x\right)}{\sqrt{3x-2}}\)

\(x^2-3x+2+\sqrt{x^2-3x+2}=0\)

\(\sqrt{x^2-3x+2}\left(\sqrt{x^2-3x+2}+1\right)=0\)\(\sqrt{x^2-3x+2}=0hay\sqrt{x^2-3x+2}+1=0\left(vl\right)\)

còn lại tự làm nhé