mình làm mẫu 2 bài nhé 2 bài kia bạn làm tương tự

1)a)\(\sqrt{4-2\sqrt{3}}-\sqrt{3}=\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{3}=\sqrt{3}+1-\sqrt{3}=1\)

\(\sqrt{10-2\sqrt{21}}+\sqrt{7}=\sqrt{\left(\sqrt{7}+\sqrt{3}\right)^2}+\sqrt{7}=\sqrt{7}+\sqrt{3}+\sqrt{7}=2\sqrt{7}+\sqrt{3}\)

2)a) \(\sqrt{12-6\sqrt{3}}-\sqrt{3}=\sqrt{\left(3-\sqrt{3}\right)^2}-\sqrt{3}=3-\sqrt{3}-\sqrt{3}=3-2\sqrt{3}\)

b) \(\sqrt{7+2\sqrt{6}}-\sqrt{3}=\sqrt{\left(1+\sqrt{6}\right)^2}-\sqrt{3}=1+\sqrt{6}-\sqrt{3}\)

3 hình tròn nha

thank you thiên giang nhé

S xung quanh \(\left(\frac{3}{5}+\frac{1}{4}\right).2.\frac{1}{3}=\frac{17}{30}m^2\)

S toàn phần là: \(\left(\frac{3}{5}.\frac{1}{4}\right).2+\frac{17}{30}=\frac{13}{15}m^2\)