Mark the letter A, B, C, or D on your answer sheet to indicate the sentence that is closest in meaning to each of the following questions:

You are in this mess right now because you didn’t listen to me in the first place.

A. If you listened to my advice in the first place, you wouldn’t be in this mess right now

B. If you listen to my advice in the first place, you will not be in this mess right now

C. If you had listened to my advice in the first place, you wouldn’t be in this mess right now

D. If you had listened to my advice in the first place, you wouldn’t have been in this mess right now

Mark the letter A, B, C, or D on your answer sheet to indicate the correct answer to each of the following questions.

By the year 2060, many people currently employed _________ the job

A. have lost

B. will be losing     

C. will have lost

D. are losing

Tên gọi cho peptit 

A. alanylglyxylalanyl. 

B. glixinalaninglyxin. 

C. glixylalanylglyxin. 

D. alanylglixylalanin. 

Mark the letter A, B, C or D on your answer sheet to indicate the most suitable response to each of the following exchanges from 10 to 11. 

Hana and Jenifer are talking about a book they have just read.

- Hana: “The book is really interesting and educational.” - Jenifer: “_______”

A. Don’t mention it 

B. That’s nice of you to say so

C. I’d love it

D. I couldn’t agree more

a) \(\dfrac{x^2+3x+2}{3x+6}=\dfrac{x^2+x+2x+2}{3\left(x+2\right)}=\dfrac{\left(x^2+x\right)+\left(2x+2\right)}{3\left(x+2\right)}=\dfrac{x\left(x+1\right)+2\left(x+1\right)}{3\left(x+2\right)}=\dfrac{\left(x+1\right)\left(x+2\right)}{3\left(x+2\right)}=\dfrac{x+1}{3}\left(1\right)\) \(\dfrac{2x^2+x-1}{6x-3}=\dfrac{2x^2+2x-x-1}{3\left(2x-1\right)}=\dfrac{2x\left(x+1\right)-\left(x+1\right)}{3\left(2x-1\right)}=\dfrac{\left(2x-1\right)\left(x+1\right)}{3\left(2x-1\right)}=\dfrac{x+1}{3}\left(2\right)\) Từ (1)và (2)=> \(\dfrac{x^2+3x+2}{3x+6}=\dfrac{2x^2+x-1}{6x-3}\) b)\(\dfrac{15x-10}{3x^2+3x-\left(2x+2\right)}=\dfrac{5\left(3x-2\right)}{3x\left(x+1\right)-2\left(x+1\right)}=\dfrac{5\left(3x-2\right)}{\left(3x-2\right)\left(x+1\right)}=\dfrac{5}{x+1}\left(3\right)\) \(\dfrac{5x^2-5x+5}{x^3+1}=\dfrac{5\left(x^2-x+1\right)}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{5}{x+1}\left(4\right)\) Từ (3) và (4) => \(\dfrac{15x-10}{3x^2+3x-\left(2x+2\right)}=\dfrac{5x^2-5x+5}{x^3+1}\)

- Lời nói không mất tiền mua Lựa lời mà nói cho vừa lòng nhau. - khó mà biết lẽ, biết lời Biết ăn, biết ở, hơn người giàu sang .

k

a)\(\dfrac{x+5}{3x-2}=\dfrac{x\left(x+5\right)}{x\left(3x-2\right)}\) b)\(\dfrac{2x-1}{4}=\dfrac{\left(2x-1\right)\left(2x+1\right)}{8x+4}\) c)\(\dfrac{2x\left(x-2\right)}{x^2-4x+4}=\dfrac{2x}{x-2}\) d) \(\dfrac{5x^2+10x}{\left(x-2\right)\left(x+2\right)}=\dfrac{5x}{x-2}\)

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