Câu trả lời:
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`
`HICL -> MgCl_{2} + H_{2}O = MgO`
`=> B`