\(\left\{{}\begin{matrix}\sqrt{x-1}+\sqrt{x+1}=\sqrt{y-1}+\sqrt{y+1}\\x^2+x+12\sqrt{y+1}=36\end{matrix}\right.\)

Cho 0<x<2 thỏa mãn: (3 * (x² + 5x - 1)) / (x² + x - 1) + 23 = (24 * (x² + 3x - 1)) / (x² + 2x - 1)

Tính T =(x²-x-2)²⁰²⁴ + 1/(x²-x)²⁰²³