Câu trả lời:
ta đặt P= 4\(\sqrt{\dfrac{2}{9}}\)+\(\sqrt{2}+\sqrt{\dfrac{1}{18}}\)Δ
P= \(\dfrac{4\sqrt{2}}{3}+\sqrt{2}+\dfrac{\sqrt{2}}{6}\)☠
P= \(\dfrac{24\sqrt{2}}{18}+\dfrac{18\sqrt{2}}{18}+\dfrac{3\sqrt{2}}{18}\)☯
P=\(\dfrac{45\sqrt{2}}{18}\)Ω
P=\(\dfrac{5\sqrt{2}}{2}\)