HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
1115×45+11151115×45+1115=1115×(45+1)=1115×(45+1)=1115×95=1115×95=3325
a, PT: Fe+H2SO4→FeSO4+H2��+�2��4→����4+�2
Fe2O3+3H2SO4→Fe2(SO4)3+3H2O��2�3+3�2��4→��2(��4)3+3�2�
b, Ta có: nH2=2,2422,4=0,1(mol)��2=2,2422,4=0,1(���)
Theo PT: nFe=nH2=0,1(mol)���=��2=0,1(���)
⇒⎧⎪⎨⎪⎩%mFe=0,1.5621,6.100%≈25,93%%mFe2O3≈100−25,93=74,07%
Some items were collected at the crime scene by the police
Ta có: nCa=640=0,15(mol)���=640=0,15(���)
PT: 2Ca+O2to→2CaO2��+�2��→2���
nCaO=nCa=0,15(mol)⇒mCaO=0,15.56=8,4(g)
slept
began
took
paid
broke
went
wore
read
đung mà
c
a.tg,v,t,cn
b.vuông
=19