\(CTTQ:\left(NH_4\right)_x\left(NO_3\right)_y\)

\(\dfrac{x}{y}=\dfrac{I}{I}=\dfrac{1}{1}\)

\(CTHH:NH_4NO_3\)

\(\left(2x-\dfrac{3}{7}\right)\left(2x^2+18\right)=0\)

\(\Rightarrow\left\{{}\begin{matrix}2x-\dfrac{3}{7}=0\\2x^2+18=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{3}{14}\\x=\varnothing\end{matrix}\right.\)

1.B

=> reading ( do sau like )

2.C

=> your ( dịch ra )