Câu trả lời:
a: ⇔20(2x−5)−30(3x−1)<12(3−x)−15(2x−1)⇔20(2x−5)−30(3x−1)<12(3−x)−15(2x−1)
=>40x-100-90x+30<36-12x-30x+15
=>-50x-70<-42x+51
=>-8x<121
=>x>-121/8
b: ⇔x2−6x+9−2(x2−1)−x+x2=0⇔x2−6x+9−2(x2−1)−x+x2=0
⇔2x2−7x+9−2x2+2=0⇔2x2−7x+9−2x2+2=0
=>11-7x=0
hay x=11/7