HOC24
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Môn học
Chủ đề / Chương
Bài học
Bài 10: Chứng Minh Rằng (CMR)
A = \(\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3+...+\left(\dfrac{1}{2}\right)^{99}< 1\)
B= \(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{99}}< \dfrac{1}{2}\)
Bài 24: Tính
14. \(\left(\dfrac{1}{7}\right)^2.\dfrac{1}{7}.49^2\)
15. \(\left(\dfrac{4}{9}+\dfrac{1}{3}\right)^2\)
11. \(25.5^3.\dfrac{1}{625}.5^2\)
12. \(4.32:\left(2^3.\dfrac{1}{16}\right)\)
13. \(5^2.3^5.\left(\dfrac{3}{5}\right)\)
2. \(\left(0,125^3\right).512\)
3. \(\left(0,25^4\right).1024\)
4. \(\dfrac{90^3}{15^3}\)
5. \(\dfrac{790^4}{79^4}\)
Tính thuận tiện
2, \(\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}\)
3, \(\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
4, \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{97.99}\)
5, \(\dfrac{3}{5.7}+\dfrac{3}{7.9}+\dfrac{3}{9.11}+...+\dfrac{3}{59.61}\)