HOC24
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Môn học
Chủ đề / Chương
Bài học
\(f,-\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{-1}{6}+-\dfrac{2}{5}=\dfrac{-2.4}{12}+\dfrac{3.3}{4.3}-\dfrac{-1}{6}+-\dfrac{2}{5}=\dfrac{1}{12}-\dfrac{-1}{6}+-\dfrac{2}{5}=\dfrac{1-\left(-1\right).2}{12}+-\dfrac{2}{5}=\dfrac{3}{12}-\dfrac{2}{5}=\dfrac{1}{4}-\dfrac{2}{5}=\dfrac{5-2.4}{20}=\dfrac{-3}{20}\)
\(f,\dfrac{1}{8}x^8+\dfrac{3}{4}x^4y^2+\dfrac{3}{2}x^2y^4+y^8\\ g,=\dfrac{1}{8}x^8-\dfrac{3}{4}x^4y^2+\dfrac{3}{2}x^2y^4-y^8\\ h,=27x^3+27x^2y^2+9xy^4+y^8\\ i,=27x^3-27x^2y^2+9xy^4-y^8\\ k,=\dfrac{1}{8}x^3+\dfrac{1}{4}x^2y+\dfrac{1}{6}xy^2+\dfrac{1}{9}y^3\\ l.=\dfrac{1}{8}x^3-\dfrac{1}{4}x^2y+\dfrac{1}{6}xy^2-\dfrac{1}{9}y^3\)
\(-3\left(x+1\right)=96-42\\ -3\left(x+1\right)=54\\ x+1=54:-3\\ x+1=-18\\ x=-19\)
\(\text{a},2=\sqrt[3]{8}\)
ma 8 <9
=> \(\sqrt[3]{9}>\sqrt[3]{8}=>\sqrt[3]{9}>2\)
\(b,\sqrt[3]{8.3}=\sqrt[3]{24};\sqrt[3]{27.2}=\sqrt[3]{54}=>\sqrt[3]{24}< \sqrt[3]{54}=>2\sqrt[3]{3}< 3\sqrt[3]{2}\)
\(\sqrt[3]{7+5\sqrt{2}}=^3\sqrt{\left(\sqrt{2}+1\right)^3}=\sqrt{2}+1\)
but
44B
45a
1.the goose is in the yard.
2.the child is tired.
3the policeman is old.
4.the mouse is hungry.
5.the sheep is ugly