Tính: \(\frac{2}{3}-\frac{1}{4}-\frac{1}{3}.\)
\(\frac{1}{3}.\)\(\frac{1}{12}.\)\(\frac{5}{12}.\)\(\frac{0}{12}.\)Hướng dẫn giải:\(\frac{2}{3}-\frac{1}{4}-\frac{1}{3}=(\frac{2}{3}-\frac{1}{3})-\frac{1}{4}=\frac{1}{3}-\frac{1}{4}=\frac{4}{12}-\frac{3}{12}=\frac{1}{12}.\)
