`Answer:`

`\frac{x-1}{34}+\frac{x-2}{34}=\frac{x-3}{32}+\frac{x-4}{31}`

`<=>\frac{x-1}{34}-1+\frac{x-2}{33}-1=\frac{x-3}{32}-1+\frac{x-4}{31}-1`

`<=>\frac{x-35}{34}+\frac{x-35}{33}=\frac{x-35}{32}+\frac{x-35}{31}`

`<=>(x-35)(\frac{1}{34}+\frac{1}{33}-\frac{1}{32}-\frac{1}{31})=0`

`<=>x-35=0`

`<=>x=35`

a) 

x – 8 + 32 = 68

x – 8 = 68 – 32 

x – 8 = 36

x = 36 + 8

x = 44

b) 

x + 8 + 32 = 68

x + 8 = 68 – 32

x + 8 = 36

x = 36 – 8

x = 28

c) 

98 – x + 34 = 43

98 – x = 43 – 34

98 – x = 9

x = 98 – 9 

x = 89 

d) 

98 + x – 34 = 43

98 + x  = 43 + 34 

98 + x = 77

x = 98 – 77 

x = 21

tick cho mink nhé!

Bg

Ta có: x² + y² = 34    (x; y \(\inℤ\))

Vì 6² hay (-6)² = 36 > 34

Nên x và y nằm trong khoảng +1; +2; +3; +4; +5; 0

Với x = +5:

x² + y² = 34

25 + y² = 34

        y² = 34 - 25

        y² = 9

        y² = 3² hay (-3)²

        y   = 3

Và ngược lại với x = +3 thì y = +5

Với x = +4

Thì y không thỏa mãn điều kiện (tự tính)

Với x = +2

Thì y không thỏa mãn

Với x = +1

Thì y cũng không thỏa mãn

Với x = 0

Cũng không thỏa mãn

Vậy x = +3 với y = +5 hoặc x = +5 với y = +3

iw

1. \(x-8+32=68\)

\(x-8=68-32\)

\(x-8=36\)

\(x=36+8\)

\(x=44\)

_____

2. \(x+8+32=68\)

\(x+8=68-32\)

\(x+8=36\)

\(x=36-8\)

\(x=28\)

_____

3. \(98-x+34=43\)

\(98-x=43-34\)

\(98-x=9\)

\(x=98-9\)

\(x=89\)

_____

4. \(98+x-34=43\)

\(98+x=43+34\)

\(98+x=77\)

\(x=77-98\)

\(x=-21\)

_____

5. \(x:5:4=800\)

\(x:5=800.4\)

\(x:5=3200\)

\(x=3200.5\)

\(x=16000\)

_____

6. \(18+x=384:8\)

\(18+x=48\)

\(x=48-18\)

\(x=30\)

_____

7. \(\left(84,6-2\times x\right):3,02=5,1\)

\(84,6-2.x=5,1.3,02\)

\(84,6-2.x=15,402\)

\(2.x=84,6-15,402\)

\(2.x=69,198\)

\(x=69,198:2\)

\(x=34,599\)

_____

8. \(x\times5=120:6\)

\(x.5=20\)

\(x=20:5\)

\(x=4\)

_____

9. \(\left(15\times24-x\right):0,25=100:0,25\)

\(\left(15.24-x\right):0,25=400\)

\(15.24-x=400.0,25\)

\(15.24-x=100\)

\(360-x=100\)

\(x=360-100\)

\(x=260\)

1,x-8+32=68

=>x-8=68-32=36

=>x=36+8=42

2,x+8+32=68

=>x+8=68-32=36

=>x=36-8=28

3,98-x+34=43

=>98-x=43-34=9

=>x=98-9=89

4,98+x-34=43

=>98+x=43+34=77

=>x=77-98=-21

5,x:5:4=800

=>x:20=800

=>x=800x20=16000

6,18+x=384:8=48

=>x=48-18=30

7,(84,6-2x):3,02=5,1

=>84,6-2x=5,1x3,02=15,402

=>2x=84,6-15,402=69,198

=>x=69,198:2=34,599

8,5x=120:6=20

=>x=20:5=4

9,(15x24-x):0,25=100:0,25=400

=>360-x=400x0,25=100

=>x=360-100=260.

1. \(...\Rightarrow x+24=68\Rightarrow x=68-24=44\)

2. \(...\Rightarrow x+40=68\Rightarrow x=68-40=28\)

3. \(...\Rightarrow3^{2\left(8+x\right)}=9=3^2\Rightarrow2\left(8+x\right)=2\Rightarrow8+x=1\Rightarrow x=-7\)

4. \(...\Rightarrow3^{2\left(8+x\right)}=77\) (bạn xem lại đề)

5. \(...\Rightarrow x:5=800.4\Rightarrow x:5=3200\Rightarrow x=3200.5=16000\)

6. \(...\Rightarrow18+x=48\Rightarrow x=48-18=30\)

7. \(...\Rightarrow84,6-2x=5,1.3,02=15,402\Rightarrow2x=84,6-15,402\Rightarrow2x=69,198\Rightarrow x=34,599\)

8. \(...\Rightarrow5.x=20\Rightarrow x=20:5=4\)

9. \(\left(360-x\right):0,25=400\Rightarrow360-x=400.0,25=100\Rightarrow x=400-100=300\)

Các bước giải chi tiết 

a)  \(\dfrac{392-x}{32}\) + \(\dfrac{390-x}{34}\) + \(\dfrac{388-x}{36}\) = -3

⇔ \(\dfrac{392-x}{32}\)+1+\(\dfrac{390-x}{34}\)+1+\(\dfrac{388-x}{36}\)+1 = 0 

⇔\(\dfrac{424-x}{32}\)+\(\dfrac{424-x}{34}\)+\(\dfrac{424-x}{36}\)=0

⇔\(\left(424-x\right)\)\(\left(\dfrac{1}{32}+\dfrac{1}{34}+\dfrac{1}{36}\right)\)=0

⇔\(424-x\) = 0\(\left(\dfrac{1}{32}+\dfrac{1}{34}+\dfrac{1}{36}\ne\forall x\right)\)

⇔\(x=424\)

b)  \(\dfrac{x-3}{3}\)- \(x\) = \(5-\dfrac{x+1}{4}\)

⇔\(\dfrac{x-3-3x}{3}\) = 5 + \(\dfrac{-\left(x+1\right)}{4}\)

⇔\(\dfrac{-2x-3}{3}\) = 5 + \(\dfrac{-x-1}{4}\)

⇔\(\dfrac{-2x-3}{3}\) = \(\dfrac{20-x-1}{4}\)

⇔\(\dfrac{-2x-3}{3}\) = \(\dfrac{-x+19}{4}\)​​

⇔ \(4\left(-2x-3\right)\) = \(3\left(-x+19\right)\)

⇔\(-8x-12\) = \(-3x+57\)

⇔\(-8x\) = \(-3x+69\)

⇔\(-5x=69\)

⇔ \(x=-\dfrac{69}{5}\)

(392-x)/32+(390-x)/34+(388-x)/36=-3
=>392-x)/32 +1 + (390-x)/34 +1 +(388-x)/36 +1=0
=>(424-x)/32+(424-x)/34+(424-x)/36=0
=>424-x=0(vì 1/32+1/34+1/36 khác 0)
=>x=424

a ) x = 5 4 x = − 5 4 b ) x = 3 2 x = − 1 2 c ) x = 3 2 x = − 1 2

d ) x = 59 40 x = 61 40 e ) x = 1 3 x = − 1 f ) x = 1 3 x = − 1

a) ! x ! + 23 = 45

    ! x ! = 45 - 23

    ! x ! = 22

-> x = 22 hoặc x = -22

b) ! x + 2 ! - 32 = 34

    ! x + 2 ! = 34 + 32

    ! x + 2 ! = 66

-> x + 2 = 66 hoặc x + 2 = -66

Nếu x + 2 = 66 thì                                          Nếu x + 2 = -66

       x = 66 - 2 = 64                                                x = -66 - 2 = -68

c) 234 + ( 34 - 23 ) + x = 546

    234 + 11 + x = 546

       245 + x = 546

       x = 546 - 245

       x = 301

a) \(\left|x\right|+23=45\)

\(\left|x\right|=45-23\)

\(\left|x\right|=22\)

\(\Rightarrow\orbr{\begin{cases}x=22\\x=-22\end{cases}}\)

vậy \(\orbr{\begin{cases}x=22\\x=-22\end{cases}}\)

b) \(\left|x+2\right|-32=34\)

\(\left|x+2\right|=34+32\)

\(\left|x+2\right|=66\)

\(\Rightarrow\orbr{\begin{cases}x+2=66\\x+2=-66\end{cases}}\Rightarrow\orbr{\begin{cases}x=64\\x=-68\end{cases}}\)

vậy \(\orbr{\begin{cases}x=64\\x=-68\end{cases}}\)

c) \(234+\left(34-23\right)+x=546\)

\(11+x=546-234\)

\(x=312-11\)

\(x=301\)

vậy \(x=301\)

a, ! x ! + 23 = 45

             ! x ! = 45 - 23

             ! x ! = 22

=> x = 22 hoặc x = - 22

b, ! x + 2 ! - 32 = 34

    ! x + 2 !       = 34 + 32

    ! x + 2 !       = 66

=> x + 2 = 66 => x = 66 - 2 = 64

hoặc x + 2 = - 66 => x = ( - 66 ) - 2 = - 68

c, 234 + ( 34 - 23 ) + x = 546

   234 + 11   + x         = 546

            245 + x         = 546

                      x        = 546 - 245 

                      x        = 301