\(\frac{4^5.9^4}{16^2.27^3}\)tinh
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tinh
a,A=\(\frac{4^5.9^4-2.69}{2^{10}.3^8+6^8.20}\)
\(A=\frac{\left(2^2\right)^5\cdot\left(3^2\right)^4-2\cdot69}{2^{10}\cdot3^8+6^8\cdot20}\)
\(A=\frac{2^{10}\cdot3^8-2\cdot3\cdot23}{2^{10}\cdot3^8+\left(2\cdot3\right)^8\cdot20}\)
\(A=\frac{6718464-1\cdot23}{6718464-6^7\cdot20}\)
\(A=\frac{6718464-23}{6718464-5598720}\)
\(A=\frac{6718441}{1119744}\)
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Thực hiện phép tính :
a) (-2.10^5 - 6.10^5 + 10^3):100
b) (2.27^2 + 3^8 - 4.9^3):9
c) (6.8^4 - 5.8^3 + 8^2):8^2
d) (5.9^2 + 3^5 - 2.3^3):3^2
\(\frac{\left(\frac{2}{3}\right)^5.9^3+\left(\frac{3}{4}\right)^8:\left(\frac{3}{16}\right)^4}{3.2^6+2.3^4}\)
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tinh \(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+20.6^8}\)
thực hiện phép tính
A=\(\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
B=\(\frac{8^5.5^8-2^5.10^9}{2^{16}.5^7+20^8}\)
C=\(\frac{4^5.9^4-2.6^4}{2^{10}.3^8+6^8.2^0}\)
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\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)
\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)
\(A=\frac{4-1}{36+12}\)
\(A=\frac{3}{48}=\frac{1}{16}\)
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Tính:
a) \(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
b) T=\(\dfrac{5^{16}.27^7}{125^5.9^{11}}\)
a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)
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Tìm số tự nhiên biết: \(\frac{4}{3.5}+\frac{8}{5.9}+\frac{12}{9.15}+...+\frac{32}{n.\left(n+16\right)}=\frac{16}{25}\)
\(\frac{4}{3.5}+\frac{8}{5.9}+\frac{12}{9.15}+...+\frac{32}{n\left(n+16\right)}=\frac{16}{25}\)
\(2\left(\frac{1}{3}-\frac{1}{5}\right)+2\left(\frac{1}{5}-\frac{1}{9}\right)+2\left(\frac{1}{9}-\frac{1}{15}\right)+...+2\left(\frac{1}{n}-\frac{1}{n+16}\right)=\frac{16}{25}\)
\(2\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{15}+...+\frac{1}{n}-\frac{1}{n+16}\right)=\frac{16}{25}\)
\(2\left(\frac{1}{3}-\frac{1}{n+16}\right)=\frac{16}{25}\)
\(\frac{1}{3}-\frac{1}{n+16}=\frac{8}{25}\)
\(\frac{1}{n+16}=\frac{1}{75}\)
\(\Rightarrow n+16=75\)
\(\Rightarrow n=59\)
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bạn Thanh Tùng DZ mình vẫn chưa hiểu tại sao \(\dfrac{8}{5.9}\) = 2.(\(\dfrac{1}{5}\) - \(\dfrac{1}{9}\))
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\(\frac{9^{3.}7+27^2.3}{3^4.2+9^2.5^2}\)\(\frac{5.2^{11}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\);\(\frac{\left(-3\right)^5.9^5.6^3.\left(-4\right)^4}{18^9}\);\(\frac{-2^4.5^2}{-8.9.119+36.78}\)
Tính:
\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(C=\frac{4^5.9^{4-2.6^9}}{2^{10}.3^8+6^8.20}\)
\(A=\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=6\)
\(B=\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}=2\)
\(C=\frac{4^5\cdot9^{4-2\cdot6^9}}{2^{10}\cdot3^8+6^8\cdot20}=0\)
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A=\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=6\)
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