x - 36 : 18 = 12

x - 2 = 12

x=  14

(x - 36) : 18 = 12

(x  - 36) = 216

x = 216 + 36

x = 352

461 + (x - 45) = 387

461 + x - 45 = 387

x = 387 - 461 + 45

x = -29 

(x-36):18=12

x-36=12x18

x-36=216

x=216+36

x= 252

x-36:18=12

x-2=12

x=14

461+(x-45)=387

x-45= 387 - 461

x-45=-74

x=-74+45

x=-29

x-36:18=12

x-2=12

x=12+2

x=14

(x-36):18=12

(x-36)=12.18

(x-36)=216

x-36=216

x=216+36

x=252

461+(x-45)=387

sai đề hay sao ấy,bạn đánh lại đi

tick nhé

khó quá

mk không giải đươc

sorry

chán thế !!!!!!

khó quá bạn lên tra google ý

461 + (x - 45) = 387

           x - 45   = 387 - 461

           x - 45   = -74

           x          = -74 + 45

           x          = -29

11 - (-53 + x) = 97

        -53 + x  = 11 - 97

        -53 + x  = -86

                 x  = -86 - -53

                 x  = -33

- (x+84) + 213 = -16

   x - 84 + 213 = -16

   x - 84           = -16 - 213

   x - 84          = -229

   x                 = -229 + 84

   x                 = -145

461 + ( x - 45 ) = 387

            x - 45  = 387 - 461

             x - 45 = - 74

                    x = - 74 + 45

                    x = - 29

Vậy x = - 29

11 - ( - 53 + x ) = 97

        - 53 + x   = 11 - 97

        - 53 + x   = - 86

                  x   = - 86 - ( - 53 ) 

                  x   = - 33

Vậy x = - 33

a) 461+(x – 45) = 387

x-45= 461-387

x-45=74

x= 74+45

x=119

Vậy...

b) 11– (53+ x) = 97

53+x= 11-97

53+x= -86

x= -86-53

x= -139

Vậy....

@Mâyy Câu a bn làm sai rùi kìa

a: =>7x=42

hay x=6

b: =>5x=35

hay x=7

c: =>x-14=16

hay x=30

d: =>36-4x=4

=>4x=32

hay x=8

e: =>x-12=144

hay x=156

f: =>3x-16=14

hay x=10

g: =>x+33=45

hay x=12

h: =>(x+9):2=39

=>x+9=78

hay x=69

a: =>7x=42

hay x=6

b: =>5x=35

hay x=7

c: =>x-14=16

hay x=30

d: =>36-4x=4

=>4x=32

a, \(x+45=54\Leftrightarrow x=9\)

b, \(x+9=3\Leftrightarrow x=-6\)

c, \(5^{2x}=5^2\Rightarrow2x=2\Leftrightarrow x=1\)

\(a,\left(x+45\right)-54=0\\ \Rightarrow x+45=54\\ \Rightarrow x=9\\ b,12\left(x+9\right)=36\\ \Rightarrow x+9=3\\ \Rightarrow x=-6\\ c,5^{2x}=25\\ \Rightarrow5^{2x}=5^2\\ \Rightarrow2x=2\\ \Rightarrow x=1\)

a)x+45=54=>x=9

b)x+9=3=>x=-6

c)x=1

Chúc em học tốt

a) -29

b)33

c) 145

a ) -29

b ) 33

c ) 145

bạn làm đúng rồi

tick mình nha

\(262+\left(2x-123\right)=283\\ \Rightarrow2x-123=21\\ \Rightarrow2x=144\\ \Rightarrow x=72\)

\(213-\left(x+84\right)=-16\\ \Rightarrow-\left(x+84\right)=-229\\ \Rightarrow x+84=229\\ \Rightarrow x=145\)

\(416+\left(x-45\right)=387\\ \Rightarrow x-45=-29\\ \Rightarrow x=16\)

help

262+(2x-123)=283

2x=  -139 +283

 2x= 144

x=72

\(a,\left(x+12\right)\left(x-6\right)>0\\ \Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x+12>0\\x-6>0\end{matrix}\right.\\\left\{{}\begin{matrix}x+12< 0\\x-6< 0\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x>-12\\x>6\end{matrix}\right.\\\left\{{}\begin{matrix}x< -12\\x< 6\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x>6\\x< -12\end{matrix}\right.\)

\(b,\left(10-x\right)\left(3-x\right)< 0\)

\(\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}10-x< 0\\3-x>0\end{matrix}\right.\\\left\{{}\begin{matrix}10-x>0\\3-x< 0\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x>10\\x< 3\left(vô.lí\right)\end{matrix}\right.\\\left\{{}\begin{matrix}x< 10\\x>3\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x< 10\\x>3\end{matrix}\right.\)

\(a,\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x+12>0\\x-6>0\end{matrix}\right.\\\left\{{}\begin{matrix}x+12< 0\\x-6< 0\end{matrix}\right.\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x>6\\x< -12\end{matrix}\right.\\ \Rightarrow x\in\left\{...;-15;-14;-13;7;8;9;...\right\}\\ b,\Rightarrow\left(x-10\right)\left(x-3\right)< 0\\ \Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-10>0\\x-3< 0\end{matrix}\right.\\\left\{{}\begin{matrix}x-10< 0\\x-3>0\end{matrix}\right.\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x>10;x< 3\left(\text{loại}\right)\\3< x< 10\end{matrix}\right.\\ \Rightarrow x\in\left\{4;5;6;7;8;9\right\}\)

\(a,\left(x+12\right)\left(x+6\right)>0\) \(khi\) \(x>6\Rightarrow x\in\left\{7,8,9,...\right\}\)

\(b,\left(10-x\right)\left(3-x\right)< 0\) \(khi\) \(x< 10\Rightarrow x\in\left\{9,8,7,...\right\}\)