a: x=5:(-1/2)=-10

b: x=8/3+1/9=25/9

c: =>x+5/6=11/21

=>x=-13/42

d: =>7/4x-5=-10/3

=>7/4x=5/3

=>x=20/21

e: =>10/3-3/4:x=-1/6

=>3/4:x=10/3+1/6=21/6=7/2

=>x=3/4:7/2=3/4*2/7=6/28=3/14

g: =>3/(x+5)=3/20

=>x+5=20

=>x=15

h: =>1-1/2+1/2-1/3+...+1/x-1/x+1=49/50

=>1-1/x+1=49/50

=>x+1=50

=>x=49

Giải:

a) \(2^5=4^x\) 

\(\Rightarrow2^5=\left(2^2\right)^x\) 

\(\Rightarrow2^5=2^{2x}\) 

\(\Rightarrow2x=5\) 

\(\Rightarrow x=\dfrac{5}{2}\) 

b) \(2.4^2.8^3.16^4=8^x\) 

\(\Rightarrow2.\left(2^2\right)^2.\left(2^3\right)^3.\left(2^4\right)^4=\left(2^3\right)^x\) 

\(\Rightarrow2.2^4.2^9.2^{16}=2^{3x}\) 

\(\Rightarrow2^{30}=2^{3x}\) 

\(\Rightarrow3x=30\) 

\(\Rightarrow x=30:3\) 

\(\Rightarrow x=10\) 

c) \(3^3:3^5=9^x\) 

\(\Rightarrow3^{-2}=\left(3^2\right)^x\) 

\(\Rightarrow3^{-2}=3^{2x}\) 

\(\Rightarrow2x=-2\) 

\(\Rightarrow x=-2:2\)

\(\Rightarrow x=-1\) 

Chúc bạn học tốt!

a) Ta có: \(2^5=4^x\)

nên \(2^{2x}=2^5\)

\(\Leftrightarrow2x=5\)

hay \(x=\dfrac{5}{2}\)

b) Ta có: \(2\cdot4^2\cdot8^3\cdot16^4=8^x\)

\(\Leftrightarrow2^{3x}=2\cdot2^5\cdot2^9\cdot2^{16}=2^{31}\)

\(\Leftrightarrow3x=31\)

hay \(x=\dfrac{31}{3}\)

c) Ta có: \(3^3:3^5=9^x\)

\(\Leftrightarrow3^{-2}=3^{2x}\)

\(\Leftrightarrow2x=-2\)

hay x=-1

a.\(\left(-12\right)x-14=-2\)

\(\left(-12\right)x=-2+14\)

\(\left(-12\right)x=12\)

\(x=12:\left(-12\right)\)

\(x=-1\)

\(b,\left(-8\right)x=\left(-5\right)\left(-7\right)-3\)

\(\left(-8\right)x=35-3\)

\(\left(-8\right)x=32\)

\(x=32:\left(-8\right)\)

\(x=-4\)

\(c,\left(-9\right)x+3=\left(-2\right)\left(-7\right)+16\)

\(\left(-9\right)x+3=14+16\)

\(\left(-9\right)x+3=30\)

\(\left(-9\right)x=30-3\)

\(\left(-9\right)x=27\)

\(x=27:\left(-9\right)\)

\(x=-3\)

tìm x

a.9/25-12/25:x=1/5

12/25:x=9/25 - 1/5

12/25:x=4/25

x=12/25 : 4/25

x=1/3

b.8/17*x+2/9=10/27

8/17*x=10/27 - 2/9

8/17*x=4/27

x=4/27 : 8/17

x=17/45

a: =>12/25:x=9/25-1/5=4/25

=>x=3

b: =>8/17x=10/27-2/9=10/27-6/27=4/27

hay x=17/54

A)    \(x-\dfrac{2}{3}=\dfrac{4}{5}\\ x=\dfrac{4}{5}+\dfrac{2}{3}\)

           \(x=\dfrac{22}{15}\)

b)\(\dfrac{7}{9}-x=\dfrac{1}{3}\\ x=\dfrac{7}{9}-\dfrac{1}{3}\\ x=\dfrac{4}{9}\)

C)\(x:\dfrac{2}{3}=\dfrac{9}{8}\\ x=\dfrac{9}{8}x\dfrac{2}{3}\\ x=\dfrac{3}{4}\)