\(125.\left(28+72\right)-25.\left(3^2.4+64\right)\)

\(=125.100-25.\left(9.4+64\right)\)

\(=125.100-25.\left(36+64\right)\)

\(=125.100-25.100\)

\(=100.\left(125-25\right)\)

\(=100.100\)

\(=10000\)

125.(28+72)-25.(3^2.4+64)

=125.100-25.(9.4+64)

=125.100-25.(36+64)

=125.100-25.100

=100.(125-25)

=100.100

=100^2

=10 000

a) \(\dfrac{28}{11}\cdot\dfrac{21}{22}\cdot9\)

\(=\dfrac{28\cdot21}{11\cdot22}\cdot9\)

\(=\dfrac{14\cdot21}{11\cdot11}\cdot9\)

\(=\dfrac{294}{121}\cdot9\)

\(=\dfrac{2646}{121}\)

b) \(=-47\left(136-36\right)\)

=\(-47.100=-4700\)

a: A=120-61x(-8)

=120+488=608

b: =47(-136+36)-(-1)

=-4700+1=-4699

c: C=(-48-304+72)+36

=-352+72+36

=-280+36=-244

A, ( - 120 ) - 18 x ( - 5 + 6 )

= ( - 120 ) - 18 x 1

= ( - 120 ) - 18

= - 138

B, 465 + ( - 38 ) + ( - 465 ) + 10 + ( - 42 )

= 0 + ( - 38 ) + 10 + ( - 42 )

= ( - 80 ) + 10

= - 70

a)  (11+159).37+(185-31):14

  =170.37+154:14

  =6290+11

  =6301

câu b bạn viết khó hiểu quá bạn viết lại đầu bài đi mik giải cho

b) 3280-(3^2.7^3.2^3.49)

\(\frac{28^{15}\cdot3^{17}}{84^{16}}\)

\(=\frac{4^{15}\cdot7^{15}\cdot3^{17}}{4^{16}\cdot7^{16}\cdot3^{16}}\)

\(=\frac{4\cdot1\cdot3}{1\cdot7\cdot1}\)

\(\frac{12}{7}\)