\(B=\dfrac{x+2}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\sqrt{x}-1}{1}=\dfrac{x+2}{\sqrt{x}}\)

Ta có: abcabc = abc000  + abc 

                      = abc x 1000 + abc 

                      = abc . (1000 + 1)

                      = abc . 1001

                      = abc . 7 . 11 . 13

suy ra abcabc là tích của abc với 7; 11; 13 => abcabc chia hết cho 7; 11 và 13

Ta có:

abcabc=abc*1001

          =abc*7*11*13

Mà abc EN

=>abcabc chia hết cho 7;11 và 13

Vậy...

\(a,=2\sqrt{2a}+3\sqrt{2a}-4\sqrt{2a}=\sqrt{2a}\\ b,=3\sqrt{5}-3+\sqrt{5}=4\sqrt{5}-3\\ c,=\dfrac{\sqrt{3}-1+\sqrt{3}+1}{\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right)}=\dfrac{2\sqrt{3}}{2}=\sqrt{3}\\ d,=-7+5-2\cdot\dfrac{2}{3}+\dfrac{1}{3}\cdot3=-2-\dfrac{4}{3}+1=-\dfrac{7}{3}\)

35 There were more than thirty people and we all had a good time at the party

36 In autumn 1621, after a good harvest, The Pilgrims celebrated to thank God 

37 We had dinner then we went to the cinema

38 What was the weather like in Egypt?

39 Last week, I went to the museum with my friend

40 What is your favorite book?

Bài 2: 

b: \(\Leftrightarrow x^2=10\)

hay \(x=\pm\sqrt{10}\)