\(A=\frac{5932+6001.5931}{5932.6001-69}=\frac{5932+6001.5931}{5931.6001+6001-69}=\frac{5932+6001.5931}{5931.6001+5932}=1\)

\(=1\)nhé

5932+6001x5931/5932x6001-69

= 5932+6001x5931/(5931+1)x6001-69

=5932+6001x5931/ 5931x6001+6001- 69

= 5932+6001x5931/5931x6001+5932

\(\dfrac{5932+6001x5931}{5932x600-69}=\dfrac{5932+6001x\left(5932-1\right)}{5932x6001-69}=\dfrac{5932+6001x5932-6001}{5932x6001-69}=\dfrac{5932x6001-\left(6001-5932\right)}{5932x6001-69}=\dfrac{5932x6001-69}{5932x6001-69}=1\)

\(=\dfrac{5931+6001\cdot5931+1}{5931\cdot6001+6001-69}\)

\(=\dfrac{5931\cdot6001+5932}{5931\cdot6001+5932}=1\)

\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5931\times6001+5932}=1\)

câu 1: 1997,1997+1998,1988+1999,1999=5994,5994

câu 2: 5932+6001x5931/5932x6001-69=360117932

tck mình nha

Tính nhanh:

a) \(\frac{254.399-145}{254+399.253}\)

\(=\)\(\frac{\left(253+1\right).399-145}{254+399.253}\)

\(=\)\(\frac{253.399+399-145}{254+399.253}\)

\(=\)\(\frac{253.399+254}{254+399.253}\)

\(=\)\(1\)

b) \(\frac{5932+6001.5931}{5932.6001-69}\)

\(=\)\(\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)

\(=\)\(\frac{5932+6001.5931}{5931.6001+6001-69}\)

\(=\)\(\frac{5932+6001.5931}{5932.6001+5932}\)

\(=\)\(1\)

a, 202292,4082

b, 36011793,2