\(M=\sqrt{\frac{8^{10}-4^{10}}{4^{11}-8^4}}\)

\(=\sqrt{\frac{2^{30}-2^{20}}{2^{22}-2^{12}}}\)

\(=\sqrt{\frac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}\)

\(=\sqrt{\frac{2^{20}}{2^{12}}}\)

\(=\sqrt{2^8}\)

\(=2^4\)

\(=16\)

=.= hok tốt!!

\(A=\sqrt{\frac{8^{10}+4^{10}}{8^4+4^{11}}}=\sqrt{\frac{2^{30}+2^{20}}{2^{22}+2^{12}}}=\sqrt{\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}}=\sqrt{\frac{2^{20}}{2^{12}}}=\sqrt{2^8}=\sqrt{\left(2^4\right)^2}\)\(=2^4=16.\)

#)Giải :

\(A=\sqrt{\frac{8^{10}+4^{10}}{8^4+4^{11}}}=\sqrt{\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}}=\sqrt{\frac{2^{30}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}}=\sqrt{\frac{2^{30}}{2^{12}}}=\sqrt{2^8}=\sqrt{256}=16\)

\(M=\sqrt{\dfrac{2^{30}-2^{20}}{2^{22}-2^{12}}}=\sqrt{\dfrac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}=\sqrt{2^8}=\sqrt{16^2}=16\)

\(A=\sqrt{\frac{2^{30}+2^{20}}{2^{12}+2^{22}}}=\sqrt{\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}}=\sqrt{2^{20-12}}=\sqrt{2^8}=2^4=16\)

\(M=\sqrt{\dfrac{8^{10}-4^{10}}{4^{11}-8^4}}\)

\(M=\sqrt{\dfrac{\left(2^3\right)^{10}-\left(2^2\right)^{10}}{\left(2^2\right)^{11}-\left(2^3\right)^4}}\)

\(M=\sqrt{\dfrac{2^{30}-2^{20}}{2^{22}-2^{12}}}\)

\(M=\sqrt{\dfrac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}\)

\(M=\sqrt{2^8}=16\)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)

\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)

\(M=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\)

\(M=\frac{2^{20}}{2^{12}}\)

\(M=\frac{2^{12}.2^8}{2^{12}}\)

\(M=2^8\)

M    = 256

\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=2^8=256\)

thank

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)

Chúc học tốt :)