x      = 9/3 - 5/8

x      =  57/24

x+5/8=9/3

x       -= 9/3 - 5/8

x        =  57/24

\(x+\dfrac{5}{8}=\dfrac{9}{3}\)

\(x=\dfrac{9}{3}-\dfrac{5}{8}=\dfrac{19}{8}\)

\(x+\dfrac{2}{-15}=\dfrac{5}{3}\)

\(x=\dfrac{9}{5}\)

\(x+\dfrac{2}{-15}=\dfrac{-5}{3}\)

\(x=\dfrac{-5}{3}-\dfrac{-2}{15}\)

\(x=\dfrac{-23}{15}\)

Lời giải:

$x+\frac{2}{-15}=\frac{-5}{3}$

$x=\frac{-5}{3}-\frac{2}{-15}=\frac{-5}{3}+\frac{2}{15}$

$x=\frac{-23}{15}$

\(x=\dfrac{1}{8}\)

`x+2/5=4/3`

`=>x=4/3-2/5`

`=> x= 20/15 -6/15`

`=>x= 14/15`

__

`x : 3/2 =2 xx 1/5`

`=> x : 3/2= 2/5`

`=> x= 2/5 xx 3/2`

`=> x= 6/10`

`=>x= 3/5`

__

Bài `5` này có `1` chút lạ ạ 

3/5 * x -1/2 = 1/5

giúp mình nhá mình đang cần gấp 

x=1/6

x=1/4

a) x = 1/6

b) x = 1/4

HT

a) 2/3 + x = 5/6

X = 5/6 - 2/3

X = 1/6

b)  x : 5/6 = 3/10

X = 5/6 x 3/10

X = 17/15

`#3107`

a)

`8x^2 - 5 = 67 `

`=> 8x^2 = 67 + 5`

`=> 8x^2 = 72`

`=> x^2 = 9`

`=> x^2 = (+-3)^2`

`=> x = +-3`

Vậy, `x \in {-3;3}`

b)

`(4x - 2)^4=16`

`=> (4x - 2) = (+-2)^4`

`=> ` TH1: `4x - 2 = 2`

`=> 4x = 4`

`=> x =1`

TH2: `4x - 2 = -2`

`=> 4x = 0`

`=> x=0`

Vậy, `x \in {0; 1}.`

a) \(8x^2-5=67\)

\(8x^2=72\)

\(x^2=9\)

\(x=3\)

Vậy x = 3

b) \(\left(4x-2\right)^4=16\)

\(\left(4x-2\right)^2=4\)

\(4x-2=2\)

\(4x=4\)

\(x=1\)

Vậy x = 1

a) x = 5/8 : 3/4

x = 5/6

b) x = 5/6 - 1/12

x = 3/4

a)x=\(\dfrac{5}{8}:\dfrac{3}{4}=\dfrac{5}{6}\)

b) x=\(\dfrac{5}{6}-\dfrac{1}{12}=\dfrac{3}{4}\)

a \(x=\dfrac{5}{8}:\dfrac{3}{4}\)

\(x=\dfrac{5}{8}\times\dfrac{4}{3}\)

\(x=\dfrac{5}{6}\)

b \(x=\dfrac{5}{6}-\dfrac{1}{12}\)

\(x=\dfrac{10}{12}-\dfrac{1}{12}\)

\(x=\dfrac{9}{12}\)

\(x=\dfrac{3}{4}\)

a) (5 + x)(x - 5) - x(x + 5) = 10

x² - 25 - x² - 5x = 10

-5x = 10 + 25

-5x = 35

x = 35 : (-5)

x = -7

b) x.(2x + 3) - 2(x² + x) = 2

2x² + 3x - 2x² - 2x = 2

x = 2

a: \(\left(x+5\right)\left(x-5\right)-x\left(x+5\right)=10\)

=>\(x^2-25-x^2-5x=10\)

=>-5x-25=10

=>-5x=35

=>x=-7

b: \(x\left(2x+3\right)-2\left(x^2+x\right)=2\)

=>\(2x^2+3x-2x^2-2x=2\)

=>x=2