\(\left(4x-1\right)^3=\frac{-1}{27}\)

\(\Rightarrow\left(4x-1\right)^3=\left(\frac{-1}{3}\right)^3\)

\(\Rightarrow4x-1=\frac{-1}{3}\)

\(\Rightarrow4x=\frac{-1}{3}+1\)

\(\Rightarrow4x=\frac{2}{3}\)

\(\Rightarrow x=\frac{2}{3}:4\)

\(\Rightarrow x=\frac{1}{6}\)

\(2.3^{x+1}=10.3^{12}+8.3^{12}\\ \Rightarrow2.3^{x+1}=3^{12}\left(10+8\right)\\ \Rightarrow2.3^{x+1}=3^{12}.18\\ \Rightarrow3^{x+1}=9.3^{12}\\ \Rightarrow3^{x+1}=3^{14}\\ \Rightarrow x+1=14\\ \Rightarrow x=13\)

Câu hỏi của Trần Ngô Hạ Uyên - Toán lớp 7 - Học toán với OnlineMath

x + 5 ⋮ x - 1 <=> ( x - 1 ) + 6 ⋮ x - 1

Vì x - 1 ⋮ x - 1 , để ( x - 1 ) + 6 ⋮ x - 1 <=> 6 ⋮ x - 1 => x - 1 ∈ Ư ( 6 ) = { + 1 ; + 2 ; + 3 ; + 6 }

Ta có bảng sau :

Vậy x ∈ { - 5 ; - 2 ; - 1 ; 0 ; 2 ; 3 ; 4 ; 7 }

<=>(x-1)+6 chia hết x-1

=>6 chia hết x-1

=>x-1\(\in\){1,-1,2,-2,3,-3,6,-6}

=>x\(\in\){2,0,3,-1,4,-2,7,-5}

cảm ơn các bn rất nhiều

\(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=4x+17\\ \Leftrightarrow x^2+6x+9-x^2+4=4x+17\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=2\)

\(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=4x+17\\ \Leftrightarrow x^2+6x+9-x^2+4=4x+17\\ \Leftrightarrow x^2-x^2+6x-4x=17-4-9\\ \Leftrightarrow2x=4\\ \Leftrightarrow x=\dfrac{4}{2}=2\)

x = 2 bạn ạ

x+12=-5-x

\(\Leftrightarrow2x=-17\)

\(\Leftrightarrow x=-\frac{17}{2}\)

Vậy ..

\(x+12=-5-x\)

\(\Rightarrow x+x=-12+5\)

\(\Rightarrow2x=-7\)

\(\Rightarrow\)Vô lý

x + 12 = -5 - x

x + x   = -5 - 12

2x       = -17

x         = (-17) : 2

x         = -8,5

Vậy x = -8,5

# HOK TỐT #

2 (x-1) - 5 (x+2) = -10

2x-2 - 5x+10 = -10

2x-5x-2+10=-10

2x-5x=-10-10+2

-3x=-18

x=6

Đặt \(A=x+\dfrac{1}{x}\)

\(A=\left(\dfrac{x}{25}+\dfrac{1}{x}\right)+\dfrac{24}{25}x\ge2\sqrt{\dfrac{x}{25x}}+\dfrac{24}{25}.5=\dfrac{26}{5}\)

\(A_{min}=\dfrac{26}{5}\) khi \(x=5\)