1000 x X = 10000

X = 10

812 × X + 188 × X = 10000

X ( 812 + 188 ) = 10000

X . 1000 = 10000

X = 10000 : 1000

X = 10

Ta có:

\(812\times x+188\times x=10000\)

\(\Leftrightarrow x\times\left(812+188\right)=10000\)

\(\Leftrightarrow x\times1000=10000\)

\(\Leftrightarrow x=10\)

\(a,1999-2000+1=\left(1999+1\right)-2000=2000-2000=0\\ b,450:5+550:5=\left(450+550\right):5=1000:5=200\\ c,188\times7+188\times4-188=188\times\left(7+4-1\right)=188\times10=1880\)

a,1999−2000+1=(1999+1)−2000=2000−2000=0b,450:5+550:5=(450+550):5=1000:5=200c,188×7+188×4−188=188×(7+4−1)=188×10=1880

a) 1999 - 2000 + 1

= ( 1999 + 1 ) - 2000

= 2000 - 2000

= 0

b) 450 : 5 + 550 : 5

= ( 450 + 550 ) : 5 

= 1000 : 5

= 200

c) 188 x 7 + 188 x 4 - 188

= ( 7 + 4 - 1 ) x 188

= 10 x 188

= 1880

a)\(\dfrac{1}{10000}+\dfrac{13}{10000}+\dfrac{25}{10000}+...+\dfrac{97}{10000}+\dfrac{109}{10000}\)

\(=\dfrac{1+13+25+...+97+109}{10000}\)

\(=\dfrac{\left(1+109\right)\left[109-1\right]:12+1}{20000}\)

\(=\dfrac{110.10}{20000}=\dfrac{11}{200}\)

b)\(\dfrac{4}{3}\times2019\times0,75\)

=\(\dfrac{4}{3}\times\dfrac{3}{4}\times2019\)

\(=2019\)

c)\(4\times5\times0,25\times\dfrac{1}{5}\times\dfrac{1}{2}\times2\)

\(=\left(4\times\dfrac{1}{4}\right)\left(5\times\dfrac{1}{5}\right)\left(2\times\dfrac{1}{2}\right)\)

\(=1\times1\times1=1\)

Ý d) đặt tính kiểu gì thế ?

2023 rồi còn ai ở đây ko 😢😢😢

= 0 nha

=00000000000

nha pn

số cần tìm là

 1 * 100 * 10000 * 10000 * 0 = 0

      đáp số 0

10000xy=10000x2

=> y=2

Vì y là giao hoán phép tính với 2

y = 2 nha bn

y= 20000:10000

y=2

150 - xx5 + 18 = 188 đúng ko ạ?

10

Cho mình xin cách lm ạ