(2x+2)2+2.(2x+2)(2x-2)+(2x-2)2
phan tich thanh nhan tu chung ( dung hang dang thuc)
Phan tich thanh nhan tu ( bang ki thuat no sung hang dang thuc)
6x^2-xy-y^2
2x^2+5xy+y^2
6x^2+2xy-4y^2
2x^2+2xy-4y^2
Phan tich thanh nhan tu ( bang ki thuat no sung hang dang thuc)
6x^2-xy-y^2
2x^2+5xy+y^2
6x^2+2xy-4y^2
2x^2+2xy-4y^2
a/ \(=2xy+6x^2-y^2-3xy=2x\left(y+3x\right)-y\left(y+3x\right)=\left(2x-y\right)\left(y+3x\right)\)
b/ \(=2x^2+5xy+y^2\)
c/ \(=-4y^2+6xy-4xy+6x^2=-2y\left(2y-3x\right)-2x\left(2y-3x\right)=\left(-2y-2x\right)\left(2y-3x\right)=-2\left(y+x\right)\left(2y-3x\right)\)
d/ \(=-4y^2-2xy+4xy+2x^2=-2y\left(2y+x\right)+2x\left(2y+x\right)=\left(-2y+2x\right)\left(2y+x\right)=-2\left(y-x\right)\left(2y+x\right)\)
Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc)
x^2+xy-2y^2
x^2-3xy-2y^2
x^2-xy-6y^2
2x^2 - 3xy -2y^2
a/ \(=2xy+x^2-2y^2-xy=x\left(2y+x\right)-y\left(2y+x\right)=\left(x-y\right)\left(2y+x\right)\)
b/ \(=x^2-3xy-2y^2\)
c/ \(=2xy-6y^2+x^2-3xy=2y\left(x-3y\right)+x\left(x-3y\right)=\left(2y+x\right)\left(x-3y\right)\)
d/ \(=xy-2y^2+2x^2-4xy=y\left(x-2y\right)+2x\left(x-2y\right)=\left(y+2x\right)\left(x-2y\right)\)
a)(x-y)(x+2y)
b) nghiệm lẻ>mìh nghĩ là sai đề
c)(x-3y)(x+2y)
d)(x-2y)(2x+y)
____________________________
li-ke cho mk nha bnLe Ngoc Bao Chau
Phan tich thanh nhan tu ( bang ki thuat bo sung hang dang thuc)
x^2+xy-2y^2
x^2-3xy-2y^2
x^2-xy-6y^2
2x^2 - 3xy -2y^2
x^2 + xy - 2y^2 = ( x^2 - 2xy + y^2 ) + 3xy - 3y^2 = ( x - y )^2 + 3y.( x - y ) = ( x - y )(x + 2y)
x^3 - 2x^2y + xy^2
phan tich da thuc thanh nhan tu a
\(=x\left(x^2-2xy+y^2\right)=x\left(x-y\right)^2\)
phan tich da thuc thanh nhan tu (x^2+2x+3).(2x^2+2x+5)-8
phan tich da thuc sau thanh nhan tu bang canh nhom hang tu x\(^3\) -2x\(^2\) +2x-13
=x^3-2x^2+2x-4-9
=(x-2)(x^2+2)-9
\(=\left(\sqrt{\left(x-2\right)\left(x^2+2\right)}-3\right)\left(\sqrt{\left(x-2\right)\left(x^2+2\right)}+3\right)\)
phan tich da thuc thanh nhan tu (x^2-x+2)^2- 2x^2 +2x -7
phan tich da thuc thanh nhan tu chung
x^6-2x^3 +1
x^4 +2x^2+1
\(x^6-2x^3+1=\left(x^3-1\right)^2\)
\(x^4+2x^2+1=\left(x^2+1\right)^2\)
a) x6 - 2x3 + 1
= (x3)2 - 2x3 + 1
= ( x3 - 1)2
b) x4 + 2x2 + 1
= ( x2)2 + 2x2 + 1
= ( x2 + 1)2
Đặt A= x^4+2x^3+4x^2+2x+1
=> A/x^2 = x^2+2x+4+2/x+1/x^2 = (x^2+1/x^2)+2(x+1/x)+4
đặt y= x+1/x => A/x^2= y^2-2+2y+4 = y^2 +2y+2= (y+1)^2 +1 >0
=>PT y^2+2y+2=0 vô nghiệm => A không thể phân tích thành nhân tử
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