\(\frac{5\cdot\left(3\cdot7^{15}-19\cdot7^{14}\right)}{7^{16}+3\cdot7^{14}}=\frac{5\cdot\left(3\cdot7-19\right)\cdot7^{14}}{\left(7^2+3\right)\cdot7^{14}}=\frac{5\cdot2\cdot7^{14}}{52\cdot7^{14}}=\frac{5\cdot2}{52}=\frac{5\cdot2}{26\cdot2}=\frac{5}{26}\)

a)

`3/5xx3/2`

`=3/5xx2/3`

`=2/5`

b)

`3/7:3/14`

`=3/7xx14/3`

`=2`

c)

`5/7xx7/10`

`=1/2`

d)

`5/11xx33/15`

`=5/11xx11/5`

`=1`

\(a,\dfrac{3}{5}:\dfrac{3}{2}=\dfrac{3}{5}\times\dfrac{2}{3}=\dfrac{6}{15}=\dfrac{2}{5}\)

\(b,\dfrac{3}{7}:\dfrac{3}{14}=\dfrac{3}{7}\times\dfrac{14}{3}=\dfrac{42}{21}=42:21=2\)

\(c,\dfrac{5}{7}\times\dfrac{7}{10}=\dfrac{35}{70}=\dfrac{1}{2}\)

\(d,\dfrac{5}{11}\times\dfrac{33}{15}=\dfrac{165}{165}=165:165=1\)

B=2^10*(2*3)^15+3^14*3*5*(2^2)^13/2^19*(2*3^2)^7*3-3^15*2^25

B=2^10*2^15*3^15+3^15+3^15*5*2^26/2^19*2^7*3^14**3-3^15*2^25

B=2^25*3^15+5*2*3^15*2^25/2*2^25*3^15-3^15*2^25

B=1*2^25*3^15+10*2^25*3^15/2*2^25*3^15-2^25*3^15

B=2^25*3^15*(1+10)/2^25*3^15*(2-1)=11/1=11

cái hàng cuối có dấu chấm đằng trước bỏ nhé cảm ơn

Bài 1: Tính

\(a.\frac{15}{16}-\frac{7}{16}=\frac{15-7}{16}=\frac{8}{16}=\frac{1}{2}\)

\(b.\frac{7}{4}-\frac{3}{4}=\frac{7-3}{4}=\frac{4}{4}=1\)

\(c.\frac{9}{5}-\frac{3}{5}=\frac{9-3}{5}=\frac{6}{5}\)

\(d.\frac{17}{49}-\frac{12}{49}=\frac{17-12}{49}=\frac{5}{49}\)

Bài 2:Rút gọn rồi tính

\(a.\frac{2}{3}-\frac{3}{9}=\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}\)

\(b.\frac{7}{5}-\frac{15}{25}=\frac{7}{5}-\frac{3}{5}=\frac{7-3}{5}=\frac{4}{5}\)

Học tốt. K cho mik nha

Trl :

Bạn kia làm đúng rồi nhé !

Học tốt nhé bạn @

40000000000000+09999999999999999999999=.....,..............,.......,........

y=41/45

8/15

m=33/20

21/22 nhé

6/7

21/35 và 20/35 nhé

14) \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\)

15) \(\sqrt{8+2\sqrt{15}}=\sqrt{5}+\sqrt{3}\)

16) \(\sqrt{10-2\sqrt{21}}=\sqrt{7}-\sqrt{3}\)

17) \(\sqrt{11+2\sqrt{18}}=3+\sqrt{2}\)

18) \(\sqrt{7+2\sqrt{10}}=\sqrt{5}+\sqrt{2}\)

19) \(\sqrt{7+4\sqrt{3}}=2+\sqrt{3}\)

20) \(\sqrt{12-2\sqrt{35}}=\sqrt{7}-\sqrt{5}\)

\(\sqrt{7-4\sqrt{3}}=\sqrt{2^2-2.2.\sqrt{3}+\left(\sqrt{3}\right)^2}=\sqrt{\left(2-\sqrt{3}\right)^2}=\left|2-\sqrt{3}\right|=2-\sqrt{3}\)

√7−4√3=√22−2.2.√3+(√3)2=√(2−√3)2=∣∣2−√3∣∣=2−√3