27 + | - 23 | - (- 50) - 32
Dùng lệnh PRINT hoặc SHOW thực hiện các phép tính sau:
2*5 | 23-35/7 | 123+27-50 | 100-(19+11) |
4*(32-7)+5*(16-4) | 25*3+3*(70-20) | 9990-998 | 2222+3333 |
Hướng dẫn:
• Để có kết quả phép tính 2*5 (2 nhân với 5), trong ngăn nhập lệnh em gõ:
PR 2*5
• hoặc:
SHOW 2*5
• Sau đó nhấn phím Enter hoặc nháy nút Excute
Kết quả:
a)-12./23/+32/-32
b)85.(35-27)-35.(85-27)
a, theo đề ra ta có:
= -12/23 + (-1 )
= -35/23
b, theo đề ra ta có:
= 85.8 - 35.58
= 680 - 2030
= - 1350
Chọn ba số rồi viết các phép tính (theo mẫu).
Mẫu:
23 + 27 = 50 50 – 27 = 23
27 + 23 = 50 50 – 23 = 27
34 + 26 = 60 60 – 34 = 26
26 + 34 = 60 60 – 26 = 34
28 + 12 = 40 40 – 28 = 12
12 + 28 = 40 40 – 12 = 28
34 + 26 = 60 60 – 34 = 26
26 + 34 = 60 60 – 26 = 34
28 + 12 = 40 40 – 12 = 28
12 + 28 = 40 40 – 28 = 12
27+23+24-32=?
Tính:
\(\left(\sqrt{32}-\sqrt{50}+\sqrt{27}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\)
\(\left(\sqrt{32}-\sqrt{50}+\sqrt{27}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\\ =\left(4\sqrt{2}-5\sqrt{2}+3\sqrt{3}\right)\left(3\sqrt{3}+5\sqrt{2}-4\sqrt{2}\right)\\ =\left(-\sqrt{2}+3\sqrt{3}\right)\left(3\sqrt{3}+\sqrt{2}\right)\\ =\left(3\sqrt{3}-\sqrt{2}\right)\left(3\sqrt{3}+\sqrt{2}\right)\\ =\left(3\sqrt{3}\right)^2-\left(\sqrt{2}\right)^2=9.3-2=25\)
\(\left(\sqrt{32}-\sqrt{50}+\sqrt{27}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\)
\(=\left(4\sqrt{2}-5\sqrt{2}+3\sqrt{3}\right)\left(3\sqrt{3}+5\sqrt{2}-4\sqrt{2}\right)\)
\(=\left(3\sqrt{3}-\sqrt{2}\right)\left(3\sqrt{3}+\sqrt{2}\right)=\left(3\sqrt{3}\right)^2-\sqrt{2}^2\)
\(=9.3-2=27-2=25\)
(\(\sqrt{32}-\sqrt{50}+\sqrt{27}\))(\(\sqrt{27}+\sqrt{50}-\sqrt{32}\))
= \(\left(4\sqrt{2}-5\sqrt{2}+3\sqrt{3}\right)\)\(\left(3\sqrt{3}+5\sqrt{2}-4\sqrt{2}\right)\)
= \(\left(3\sqrt{3}-\sqrt{2}\right)\)\(\left(3\sqrt{3}+\sqrt{2}\right)\)
= \(\left(3\sqrt{3}\right)^2-\left(\sqrt{2}\right)^2\)
= 27 - 2 = 25
Tính :
\(\left(\sqrt{32}-\sqrt{50}+\sqrt{27}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\)
\(\left(\sqrt{32}-\sqrt{50}+\sqrt{27}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\)
\(=\left(4\sqrt{2}-5\sqrt{2}+3\sqrt{3}\right)\left(3\sqrt{3}+5\sqrt{2}-4\sqrt{2}\right)\)
\(=\left(3\sqrt{3}-\sqrt{2}\right)\left(3\sqrt{3}+\sqrt{2}\right)\)
\(=27-2\)
\(=25\)
\(\left(\sqrt{32}-\sqrt{50}+\sqrt{27}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\)
\(\Leftrightarrow\left(4\sqrt{2}+3\sqrt{3}-5\sqrt{2}\right)\left(\sqrt{27}+\sqrt{50}-\sqrt{32}\right)\)
\(\Leftrightarrow\left(4\sqrt{2}+3\sqrt{2}-5\sqrt{2}\right)\left(3\sqrt{3}+5\sqrt{2}-4\sqrt{2}\right)\)
\(\Leftrightarrow\left(3\sqrt{3}-\sqrt{2}\right)\left(3\sqrt{3}+5\sqrt{2}-4\sqrt{2}\right)\)
\(\Leftrightarrow\left(3\sqrt{3}-\sqrt{2}\right)\left(3\sqrt{3}+2\right)\)
\(\Leftrightarrow\left(3\sqrt{3}\right)^2-\left(\sqrt{2}\right)^2\)
\(\Rightarrow25\)
Vậy: BT = 25
P/s: từ dòng thứ 2 trở xuống bạn tự phân ... Vấn đề là ở bạn thôi :)))
\(=\left(\sqrt{27}\right)^2-\left(\sqrt{50}-\sqrt{32}\right)^2\)
\(=27-2=25\)
Tính nhanh :
a) 23 . 55 - 45 . 23 + 230
b) 71 . 66 - 41 . 71 - 71
c) 11 . 50 + 50 . 22 - 100
d) 54 . 27 - 27 . 50 + 50
a. = 23 . (55-45) + 230
= 23 . 10 +230
= 230 + 230
= 460
b. = 71 . (66 - 41 - 1)
= 71 . 24
= 1704
c. = 50 . (11 + 22) - 100
= 50 . 33 - 100
= 1650 - 100
= 1550
d. = 27. (54 - 50) + 50
= 27 . 4 + 50
= 108 + 50
= 158
a) 23.55-45.23+230
=23.(55-45)+230
=23.10+230
=230+230
=460
b) 71.66-41.71-71
=71.(66-41-1)
=71.24
=1704
c) 11.50+50.22-100
=50.(11+22)-100
=50.33-100
=1550
d) 54.27-27.50+50
=27.(54-50)+50
=27.4+50
=108+50
=158
# Bé_Bông #
a, 23 . 55 -45 . 23 + 230
23 . ( 55 - 45) + 230
23 . 10 + 230
230 + 230
4600
b, 71 . 66 - 41 . 71 - 71
71 . ( 66 - 71 - 1)
71 . ( -4)
-248
c, 11 . 50 + 50 . 22 - 100
11 . ( 50 + 50 ) - 100
11 . 100 - 100
1100 - 100
1000
d, 54 . 27 - 27 . 50 + 50
27 . ( 54 - 50 ) + 50
27 . 4 + 50
108 + 50
158
tck mk nhé
thank you
bỏ ngoặc rồi tính
a> (38-42+14)-(25-27-15)
b.-(21-32)-(-12+32)
c>-(12+21-23)-(23-21)
50+ 64-27-3+32=
Bài toán 7 : Thực hiện phép tính.
a) 27 . 75 + 25 . 27 - 150;
b) 142 - [50 - (23.10 - 23.5)]
c) 375 : {32 – [ 4 + (5. 32– 42)]} – 14
a) `27 .75 + 25.27 -150`
`=27 xx (75 + 25)-150`
`=27 xx 100-150`
`=2700-150`
`=2550`
b) `142-[50-(2^3 .10-2^3 .5)]`
`=142-[50-2^3 .(10-5)]`
`=142-(50-8 .5)`
`=142-(50-40)`
`=142-10`
`=132`
c) `375:{32-[4+(5.3^2-42)]}-14`
`=375:{32-[4+(45-42)]}-14`
`=375:[32-(4+3)]-14`
`=375: 25 -14`
`=15-14`
`=1`
a. 27 . 75 + 25 . 27 - 150
= 27. (75 + 25) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
b. 142 - [50 - (23.10 - 23.5)]
= 142 - [50 - (8 . 10 - 8 . 5)]
= 142 - {50 - [8 . (10 - 5)]}
= 142 - (50 - 40)
= 142 - 10
= 132
c. 375 : {32 – [ 4 + (5. 32 – 42)]} – 14
= 375 : {32 – [ 4 + (5. 9 – 42)]} – 14
= 375 : {32 – [ 4 + (45 – 42)]} – 14
= 375 : {32 – [ 4 + 3]} – 14
= 375 : {32 –7} – 14
= 375 : 25 - 14
= 15 - 14
= 1