a) Ta có: \(4567+1234-4567-\left(-66\right)\)

\(=4567-4567+1234+66\)

\(=1234+66=1300\)

b) Ta có: \(2004-15+54-2004-54\)

\(=\left(2004-2004\right)+\left(54-54\right)-15\)

\(=0+0-15\)

\(=-15\)

c) Ta có: \(-45789-357-45789+57\)

\(=-91578-300=-91878\)

bài 1

a)-7105-(155-7105)+355
 =-7105 -155 +7105 +355
 =(-7105 + 7105)+(-155 + 355)

 =0 + 200

=200
 

b)(35−815)−(795−65)b)(35-815)-(795-65)

=−780−730=-780-730

=−1510

$a\left)\right(-7105)-(155-7105)+355$

$=(-7105)-155+7105+335$

$=\left[\right(-7105)+7105]+(355-155)$

$=0+200$

$=200$

$b\left)\right(35-815)-(795-65)$

$=35-815-795+65$

$=(35+65)+\left[\right(-815)-795]$

$=100+(-1610)$

$=-1510$

c)5−197−2015−2015c)5−197−2015−2015

=(5−197)+[(−2015)−2015]=(5−197)+[(−2015)−2015]

=(−192)+(−4330)=(−192)+(−4330)

=−4522=−4522

d)4567+1234−4567−(−66)d)4567+1234−4567−(−66)

=(4567−4567)+[1234−(−66)]=(4567−4567)+[1234−(−66)]

=0+1300=0+1300

=1300
 

e)2004−15+54−2004−54e)2004−15+54−2004−54

=(2004−2004)+(54−54)−15=(2004−2004)+(54−54)−15

=0+0−15=0+0−15

=−15
 

g)1259−1409−12+1259+1409g)1259−1409−12+1259+1409

=(1259+1259)+(1409−1409)−12=(1259+1259)+(1409−1409)−12

=2518+0−12=2518+0−12

=2506

Bài 1: 

a) 4√24 - 3√54 + 5√6 - √150

= 8√6 - 9√6 + 5√6 - 5√6

= -√6

a: \(=4\cdot2\sqrt{6}-3\cdot3\sqrt{6}+5\sqrt{6}-5\sqrt{6}\)

\(=8\sqrt{6}-9\sqrt{6}=-\sqrt{6}\)

b: \(=2\left(3-2\sqrt{2}\right)-2\left(3+2\sqrt{2}\right)\)

\(=6-4\sqrt{2}-6-4\sqrt{2}=-8\sqrt{2}\)

c: \(=\sqrt{3-\sqrt{5}}-\sqrt{3+\sqrt{5}}\)

\(=\dfrac{\sqrt{6-2\sqrt{5}}-\sqrt{6+2\sqrt{5}}}{\sqrt{2}}\)

\(=\dfrac{\sqrt{5}-1-\sqrt{5}-1}{\sqrt{2}}=-\dfrac{2}{\sqrt{2}}=-\sqrt{2}\)

b: \(=32+\dfrac{5}{16}-3\cdot32\)

=-64+5/16

=-1019/16

a: \(\dfrac{16}{15}\cdot\dfrac{-5}{14}\cdot\dfrac{54}{24}\cdot\dfrac{56}{21}\)

\(=\dfrac{16}{24}\cdot\dfrac{-5}{15}\cdot\dfrac{54}{21}\cdot\dfrac{56}{14}\)

\(=\dfrac{2}{3}\cdot\dfrac{-1}{3}\cdot\dfrac{18}{7}\cdot4\)

\(=\dfrac{-2\cdot2\cdot4}{7}=-\dfrac{16}{7}\)

b: \(\dfrac{7}{3}\cdot\dfrac{-5}{2}\cdot\dfrac{15}{21}\cdot\dfrac{4}{-5}\)

\(=\dfrac{7}{3}\cdot\dfrac{5}{7}\cdot\dfrac{5}{2}\cdot\dfrac{4}{5}\)

\(=\dfrac{5}{3}\cdot\dfrac{4}{2}=\dfrac{5}{3}\cdot2=\dfrac{10}{3}\)

c: \(\left(-\dfrac{2}{5}+\dfrac{1}{3}\right)\left(\dfrac{3}{2}-\dfrac{3}{7}\right)\)

\(=\dfrac{-2\cdot5+3}{15}\cdot\dfrac{3\cdot7-3\cdot2}{14}\)

\(=\dfrac{-7}{15}\cdot\dfrac{15}{14}=\dfrac{-7}{14}=-\dfrac{1}{2}\)

d: \(\left(\dfrac{1}{2}-\dfrac{1}{3}\right)\left(5-\dfrac{1}{4}\right)\)

\(=\dfrac{3-2}{6}\cdot\dfrac{20-1}{4}\)

\(=\dfrac{1}{6}\cdot\dfrac{19}{4}=\dfrac{19}{24}\)

e: \(\left(\dfrac{4}{5}\right)^2=\dfrac{4^2}{5^2}=\dfrac{16}{25}\)

a/=68

a) 125 : 25 + 12 . 4      c) 2680 + [ 10 . ( 4³ -54 ) : 5² + 2⁴]

= 5 + 48                        = 2680 + [ 10 . ( 64 - 54 ) : 25 + 16]

= 53                              = 2680 + [ 10 . 10 : 25 + 16]

                                     = 2680 + [ 100 : 25 + 16]

                                     = 2680 + [ 4 + 16 ]

                                     = 2680 + 20

                                     = 2700

a/ 125 : 25 + 12 . 4

=5+48

=53

c/ 2680 + [ 10 . ( 4³ - 54 ) : 5² + 2⁴ ]

=2680 +  [ 10 . 10 : 25 + 16 ]

= 2680 + 20

=2700

b/ 25 - ( 62 - 75 ) + ( - 38 )

= 25 - (- 13) + (- 38) 

=25 + 13 + (- 38)

=38 + (-38)

=0

\(a.\)

\(\dfrac{17}{8}:\left(\dfrac{27}{8}+\dfrac{11}{2}\right)\)

\(=\dfrac{17}{8}:\left(\dfrac{27+44}{8}\right)=\dfrac{17}{8}:\dfrac{71}{8}=\dfrac{17}{8}\cdot\dfrac{8}{71}=\dfrac{17}{71}\)

\(b.\)

\(\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8}{15}-\dfrac{69}{60}\cdot\dfrac{5}{23}\right):\dfrac{51}{54}\)

\(=\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8}{15}-\dfrac{1}{4}\right):\dfrac{51}{54}\)

\(=\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8\cdot4-15}{60}\right):\dfrac{51}{54}\)

\(=\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\dfrac{17}{60}:\dfrac{51}{54}\)

\(=\dfrac{28}{15}\cdot\dfrac{1}{16}\cdot3+\dfrac{17}{60}\cdot\dfrac{54}{51}\)

\(=\dfrac{7}{20}+\dfrac{3}{10}\)

\(=\dfrac{7+3\cdot2}{20}=\dfrac{13}{20}\)

Sai kìa phải bằng 11/20

a) 23 phút 25 giây-15 phút 12 giây=8 phút 13 giây

b) 54 phút 21 giây-21 phút 34 giây=32 phút 47 giây

c) 22 giờ 15 phút-12 giờ 35 phút=9 giờ 40 phút

a) 23 phút 25 giây  15 phút 12 giây= 8  phút 13 giây

b) 54 phút 21 giây  21 phút 34 giây= 32 phút 47 giây

c) 22 giờ 15 phút  12 giờ 35 phút= 9 phút 40 giây

a) 23 phút 25 giây-15 phút 12 giây=8 phút 13 giây

b) 54 phút 21 giây-21 phút 34 giây=32 phút 47 giây

c) 22 giờ 15 phút-12 giờ 35 phút=9 giờ 40 phút

a) 23 phút 25 giây  15 phút 12 giây= 8  phút 13 giây

b) 54 phút 21 giây  21 phút 34 giây= 32 phút 47 giây

c) 22 giờ 15 phút  12 giờ 35 phút= 9 phút 40 giây