2022x2023-123/1900+2021x2023
a)2021+2020x2022/2021x2022-1
b)2022+2021x2023/2022x2023-1
Ai giúp mình nhanh nhanh với!SOS!
a. \(\dfrac{2021+2020.2022}{2021.2022-1}\)
\(\dfrac{2021.2022-2022+2021}{2021.2022-1}=\dfrac{2021.2022-1}{2021.2022-1}=1\)
\(b.\dfrac{2022+2021.2023}{2022.2023-1}=\dfrac{2021.2023-2023+2022}{2022.2023-1}\)
\(=\dfrac{2021.2023-1}{2022.2023-1}\)
Bài tính thuận tiện
2023x2022-2021x2023
2023x2022-2021x2023
= 2023 x (2022 - 2021)
= 2023 x 1
= 2023
2023 x 2022 - 2021 x 2023
= 2023 x (2022 - 2021)
= 2023 x 1
= 2023
1/2022x2023 + 1/2023x2024 + 1/2024
1/(2022 × 2023) + 1/(2023 × 2024) + 1/2024
= 1/2022 - 1/2023 + 1/2023 - 1/2024 + 1/2024
= 1/2022
= 1/2022 - 1/2023 + 1/2023 - 1/2024 + 1/2024 x 1
= 1 - 1/2022
= 2021/2022
mik ko biết đúng ko!
a=1/1x3=1/3x5+1/5x7+....+1/2019x2021+1/2021x2023
B = 1/2x3 + 1/3x4 + 1/4x5 * ... x + 1/ 2022x2023
\(B=\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{2022.2023}\)
\(B=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{2022}-\dfrac{1}{2023}\)
\(B=\dfrac{1}{2}-\dfrac{1}{2023}=\dfrac{2021}{4046}\)
Giúp e bài bày ạ. Tính nhanh: 2022x2023-3/2023x2021+2020
tính bằng cách thuận tiện đi mà
2022x2023-1
___________
2023x2021+2022
s=1/1X2+1/2X3+1/3X4+1/4+.....+1/2022X2023
21 + 34 + 36 - 12
= (34 + 36) + (21 - 12)
= 70 + 9
= 79
Chúc bn học tốt!
Tính
D = \(\dfrac{1}{1x2}+\dfrac{1}{2x3}+\dfrac{1}{3x4}+....+\dfrac{1}{2022x2023}\)