Tính \(\frac{7.13^{15}-3.13^{13}}{26.\left(16^9\right)^6}\)
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Tính
a, \(\frac{\left(21\right)^{15}.49^{11}.5^6}{\left(63\right)^{14}.7}\)
b, \(\frac{7.13^{15}-3.13^{13}}{26.\left(16^9\right)^6}\)
nói cách làm nhé
Tính nhanh (nếu có thể):
a,\(\frac{27^2.8^5}{66.32^3}\)
b, \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
c, \(\frac{\left(17\frac{8}{19}-16\frac{9}{18}\right).\left(17,5+16\frac{17}{51}-32\frac{15}{22}\right)}{\frac{7}{3.13}+\frac{7}{13.3}+\frac{7}{23.33}}\)
a)\(\frac{243}{22}\)
b)\(\frac{4}{5}=0,8\)
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bài 1 tính A frac{25}{54}+frac{3}{75}:frac{left(frac{39}{65}+0,415-frac{33}{600}right):frac{21}{9}}{7^2-15,25+13frac{15}{36}-16frac{17}{9}}bài 2 tính ti số frac{A}{B}biết : Afrac{4}{7.13}+frac{6}{7.41}+frac{9}{10.41}++frac{7}{10.57}Bfrac{7}{19.31}+frac{5}{19.43}+frac{3}{23.43}+frac{11}{23.57}
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bài 1 tính
A = \(\frac{25}{54}\)+\(\frac{3}{75}\):\(\frac{\left(\frac{39}{65}+0,415-\frac{33}{600}\right):\frac{21}{9}}{7^2-15,25+13\frac{15}{36}-16\frac{17}{9}}\)
bài 2 tính ti số \(\frac{A}{B}\)biết : \(A=\frac{4}{7.13}+\frac{6}{7.41}+\frac{9}{10.41}++\frac{7}{10.57}\)
\(B=\frac{7}{19.31}+\frac{5}{19.43}+\frac{3}{23.43}+\frac{11}{23.57}\)
a)Tính\(\frac{\left(17\frac{8}{19}-16\frac{9}{18}\right)\left(17,5+16\frac{17}{51}-32\frac{15}{22}\right)}{\frac{7}{3.13}+\frac{7}{13.23}+\frac{7}{23.33}}\)
b) Chứng tò rằng:\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}\)\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
phần a dễ bạn tự làm đi tử thì bạn tính như bình thường còn mẫu thì:7.(\(\frac{1}{3.13}\)+\(\frac{1}{13.23}\)+\(\frac{1}{23.33}\))
\(\frac{7}{10}\).(\(\frac{1}{3}\)-\(\frac{1}{33}\))=\(\frac{7}{33}\)
b)(1+1/3+1/5+..+1/199)-(1/2+1/4+...+1/200)
(1+1/2+1/3+...+1/199+1/200)-(1/2+1/2+1/4+1/4+...+1/200+1/200)
=1+1/2+1/3+...+1/199+1/200-(1+1/2+1/3+...+1/100)
=1/101+1/102+...+1/200
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https://olm.vn/hoi-dap/question/60726.html
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1)Tính
a.\(\frac{3^6\cdot45^4-15^{13}\cdot5^{-9}}{27^4\cdot25^3+45^6}\)
b.\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3\div\left(\frac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
bài 1 : tính
a)\(\frac{-5}{13}-\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)\) b) \(\left(\frac{3}{9}-\frac{9}{18}\right)+\frac{3}{6}-\left(\frac{1}{3}-\frac{1}{2}\right)-\frac{5}{15}\) c) \(\frac{9}{18}+\frac{16}{32}-\frac{12}{46}-\frac{9}{17}\) d) \(\left(\frac{14}{18}+\frac{-16}{27}\right)-\left(\frac{2}{3}-\frac{5}{15}\right)\)
a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)
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Bỏ dấu ngoặc rồi tính các tổng sau:
\(\begin{array}{l}a)\frac{{17}}{{11}} - \left( {\frac{6}{5} - \frac{{16}}{{11}}} \right) + \frac{{26}}{5}\\b)\frac{{39}}{5} + \left( {\frac{9}{4} - \frac{9}{5}} \right) - \left( {\frac{5}{4} + \frac{6}{7}} \right)\end{array}\)
\(\begin{array}{l}a)\frac{{17}}{{11}} - \left( {\frac{6}{5} - \frac{{16}}{{11}}} \right) + \frac{{26}}{5}\\ = \frac{{17}}{{11}} - \frac{6}{5} + \frac{{16}}{{11}} + \frac{{26}}{5}\\ = (\frac{{17}}{{11}} + \frac{{16}}{{11}}) + (\frac{{26}}{5} - \frac{6}{5})\\ = \frac{{33}}{{11}} + \frac{{20}}{5}\\ = 3 + 4\\ = 7\\b)\frac{{39}}{5} + \left( {\frac{9}{4} - \frac{9}{5}} \right) - \left( {\frac{5}{4} + \frac{6}{7}} \right)\\ = \frac{{39}}{5} + \frac{9}{4} - \frac{9}{5} - \frac{5}{4} - \frac{6}{7}\\ = (\frac{{39}}{5} - \frac{9}{5}) + (\frac{9}{4} - \frac{5}{4}) - \frac{6}{7}\\ = \frac{{30}}{5} + \frac{4}{4} - \frac{6}{7}\\ = 6 + 1 - \frac{6}{7}\\ = 7 - \frac{6}{7}\\ = \frac{{49}}{7} - \frac{6}{7}\\ = \frac{{43}}{7}\end{array}\)
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1,Tính : ( Hãy tính nhanh nếu có thể )
a,\(\frac{3^6.45^4-15^{13}.\left(\frac{1}{5}\right)^9}{27^4.25^3+45^6}\)
b,\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)
Thực hiện phép tính (hợp lí nếu có thể):1,frac{-1}{3}-frac{-3}{5}-frac{1}{6}+frac{1}{43}-frac{-3}{7}+frac{-1}{2}-frac{1}{35}
2,left(-frac{1}{3}+frac{7}{13}right)-left(frac{-16}{24}+frac{6}{26}+frac{9}{13}right)3,frac{-7}{3}-left[frac{2}{5}-left(frac{1}{3}+frac{-5}{25}right)right]
4,left(2frac{1}{4}-3frac{1}{5}right)-left[frac{-3}{4}+left(frac{4}{5}-2019right)right]
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Thực hiện phép tính (hợp lí nếu có thể):
\(1,\frac{-1}{3}-\frac{-3}{5}-\frac{1}{6}+\frac{1}{43}-\frac{-3}{7}+\frac{-1}{2}-\frac{1}{35}\\ \\ 2,\left(-\frac{1}{3}+\frac{7}{13}\right)-\left(\frac{-16}{24}+\frac{6}{26}+\frac{9}{13}\right)\)\(3,\frac{-7}{3}-\left[\frac{2}{5}-\left(\frac{1}{3}+\frac{-5}{25}\right)\right]\\ 4,\left(2\frac{1}{4}-3\frac{1}{5}\right)-\left[\frac{-3}{4}+\left(\frac{4}{5}-2019\right)\right]\)