Tính:
\(6^2.6^4-4^3\left(3^6-1\right)\)
Những câu hỏi liên quan
Bài 1: Tính một cách hợp líd) (^{2^2} : dfrac{4}{3} - ^{dfrac{1}{2}} ) x dfrac{6}{5} - 17h) dfrac{left(-1right)^3}{15} + left(-dfrac{2}{3}right)^2 : 2dfrac{2}{3} - left|-dfrac{5}{6}right|k) dfrac{2.6^9-2^5.18^4}{2^2.6^8}n) 3 - left(-dfrac{7}{8}right)^0 + left(dfrac{1}{2}right)^3 . 16Mg giải gấp giúp mình ạ
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Bài 1: Tính một cách hợp lí
d) (\(^{2^2}\) : \(\dfrac{4}{3}\) - \(^{\dfrac{1}{2}}\) ) x \(\dfrac{6}{5}\) - 17
h) \(\dfrac{\left(-1\right)^3}{15}\) + \(\left(-\dfrac{2}{3}\right)^2\) : \(2\dfrac{2}{3}\) - \(\left|-\dfrac{5}{6}\right|\)
k) \(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}\)
n) 3 - \(\left(-\dfrac{7}{8}\right)^0\) + \(\left(\dfrac{1}{2}\right)^3\) . 16
Mg giải gấp giúp mình ạ
d: \(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(3-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\dfrac{5}{6}\cdot\dfrac{6}{5}-17=1-17=-16\)
h: \(\dfrac{\left(-1\right)^3}{15}+\left(-\dfrac{2}{3}\right)^2:2\dfrac{2}{3}-\left|-\dfrac{5}{6}\right|\)
\(=-\dfrac{1}{15}+\dfrac{-8}{27}:\dfrac{8}{3}-\dfrac{5}{6}\)
\(=-\dfrac{1}{15}-\dfrac{1}{9}-\dfrac{5}{6}\)
\(=\dfrac{-6-10-75}{90}=\dfrac{-91}{90}\)
k: \(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\)
\(=\dfrac{2^{10}\cdot3^9-2^5\cdot2^4\cdot3^8}{2^2\cdot2^8\cdot3^8}\)
\(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^8}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}\)
\(=\dfrac{5}{2}\)
n: \(3-\left(-\dfrac{7}{8}\right)^0+\left(\dfrac{1}{2}\right)^3\cdot16\)
\(=3-1+\dfrac{1}{8}\cdot16\)
=2+2
=4
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Tính:
a)\(2^3.7+3^2.6=\)
b)\(7^3-6^3-5^3=\)
c)\(6^4-2^5.3^3=\)
d)\(\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right)\left(2^4-4^2\right)=\)
a)56+48=104
b)343-216-125=2
c)1296-32*27=1296-864=432
d)=0(vì các số *với 0 đều =0(\(2^4\)-4\(^2\)=0)
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a) \(2^3.7+3^2.6=8.7+9.6\)
\(=56+54\)
\(=110\)
b) \(7^3-6^3-5^3=343-216-125\)
\(=2\)
c) \(6^4-2^5.3^3=1296-32.27\)
\(=1296-864\)
\(=432\)
d) \(\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right)\left(2^4-4^2\right)\)
\(=\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right).0\)
\(=0\)
NHỚ K CHO MÌNH NHÉ !
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Thức hiện phép tính
\(6^2.6^4-4^3\left(3^6-1\right)\)
=32.22.34.24-26(36-1)
=26.36-26(36-1)
=26(36-36+1)=26=64
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62.64 - 43 (36 - 1)
= (3.2)2 . (3.2)4 - (22)3 (36 - 1)
= 32. 22 . 34. 24 - 26 (36 - 1)
= 26. 36 - 26 (36 - 1)
= 26. (36 - 36 +1 )
= 26 . 1 = 26 = 64
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1) \(25^{10}.\left(\dfrac{1}{5}\right)^{20}+\left(\dfrac{-3}{4}\right)^8.\left(\dfrac{-4}{3}\right)^8-2018^0\)
2) \(\left(\dfrac{5}{2}-\dfrac{4}{3}\right).\dfrac{6}{7}+\left(\dfrac{-3}{2}\right)^5:\left(\dfrac{-3}{2}\right)^3\)
3) \(\dfrac{4^5.9^4-2.6^9}{3^8.2^{10}+6^8.20}\)
1: \(=5^{20}\cdot\left(\dfrac{1}{5}\right)^{20}+\left(\dfrac{-3}{4}\cdot\dfrac{-4}{3}\right)^8-1\)
=1+1-1=1
2: \(=\dfrac{15-8}{6}\cdot\dfrac{6}{7}+\left(-\dfrac{3}{2}\right)^2\)
=1+9/4
=13/4
3: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{3^8\cdot2^{10}+2^{10}\cdot3^8\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{3^8\cdot2^{10}\cdot6}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
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Thực hiện phép tính = cách biến đổi thành thừa số nguyên tố:
a,\(4.\left(\frac{-1}{2}\right)^3+\frac{1}{2}\)
b,\(\left(\frac{1}{6}\right)^2.6^2+\frac{\left(0,6\right)^2}{\left(0,2\right)^6}\)
a)4.-1/8+1/2=-4/8+1/2
b)1/36.36+(0,6^1)^2/(0,2^3)^2
=1+0,36/0,000064
=1+5625
=5626
Tính
a, \(\frac{2^5.8^4.4^3}{16^6}\)
b, \(\frac{\left(\frac{1}{6}\right)^2.6^2+\left(0,6\right)^5}{\left(0,2\right)^5}\)
c, \(\left(\frac{3}{5}-\frac{3}{4}\right).\left(\frac{2}{6}-\frac{1}{5}\right)^2\)
d, \(\frac{8^4.3^6}{2^7.65}\)
e, \(\frac{2^5.49^2}{4^3.7^3}\)
a) \(\frac{2^5\cdot2^{12}\cdot2^6}{2^{24}}=\frac{2^{23}}{2^{24}}=\frac{1}{2}\)
Các phần kia tương tự, à bạn đăng 1 2 câu hỏi 1 lần thôi, đăng nhiều quá ko ai trả lời đâu
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Thế à ! Vậy bạn hãy nhấp vào https://h.vn/hoi-dap/question/646555.html?pos=1792187 mà xem
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1. Thực hiện phép tính:
a. \(3x^n\left(6x^{n-3}+1\right)-2x^n\left(9x^{n-3}-1\right)\)
b. \(5^{n+1}-4.5^n\)
c. \(6^2.6^4-4^3\left(3^6-1\right)\)
a:
=\(18x^{2n-3}+3x^n-18^{2n-3}+2x^n\)
\(=5x^n\)
b: \(=5^n\cdot5-4\cdot5^n=5^n\)
c: \(=6^6-4^3\cdot3^6+4^3\)
\(=2^6\cdot3^6-2^6\cdot3^6+64=64\)
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a,frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}
b,frac{27^2.8^5}{6^6.32^3}+frac{3^4.4^4}{2^2.6^2}
c,left(1+frac{1}{1.3}right)left(1+frac{1}{2.4}right)left(1+frac{1}{3.5}right)........left(1+frac{1}{20.22}right)
d,frac{3}{2}+frac{7}{6}+frac{13}{12}+frac{21}{20}+.....+frac{91}{90}
e,left(-2^2right)+sqrt{36}-sqrt{9}+sqrt{25} 20).20)
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a,\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
b,\(\frac{27^2.8^5}{6^6.32^3}+\frac{3^4.4^4}{2^2.6^2}\)
c,\(\left(1+\frac{1}{1.3}\right)\)\(\left(1+\frac{1}{2.4}\right)\)\(\left(1+\frac{1}{3.5}\right)\)........\(\left(1+\frac{1}{20.22}\right)\)
d,\(\frac{3}{2}\)+\(\frac{7}{6}\)+\(\frac{13}{12}+\frac{21}{20}+.....+\frac{91}{90}\)
e,\(\left(-2^2\right)+\sqrt{36}-\sqrt{9}+\sqrt{25}\) 20).20)
Tính
a, \(\frac{\left(\frac{1}{6}\right)^2.6^2+\left(0,6\right)^5}{\left(0,2\right)^5}\)
b, \(\left(-3\right)^2+\left(\frac{-1}{2}\right)^3-\left(3,5\right)^0\)
c, \(2\frac{1}{4}+\frac{2}{5}.0,3-\left(\frac{12}{5}-3\right)^2\)
mình cần tính nhanh cơ hoặc tính ra đày đủ đó
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