Ta có: \(\left|97\dfrac{2}{3}-125\dfrac{3}{5}\right|+97\dfrac{2}{5}-125\dfrac{1}{3}\)

\(=\left|97+\dfrac{2}{3}-125-\dfrac{3}{5}\right|+97+\dfrac{2}{5}-125-\dfrac{1}{3}\)

\(=\left|-28+\dfrac{1}{15}\right|-28+\dfrac{1}{15}\)

\(=\left|\dfrac{1}{15}-28\right|-28+\dfrac{1}{15}\)

\(=28-\dfrac{1}{15}-28+\dfrac{1}{15}\)

\(=0\)

A=[(38+17)+125]+29

A=175+29

A=204

B=312.3

B=936

C=1+1+1+1+1

C=5

D=(125:5).(36:9)

D=25.4

D=100

Ta có: \(\left|97\dfrac{2}{3}-123\dfrac{3}{5}+97\dfrac{2}{5}-125\dfrac{1}{3}\right|\)

\(=\left|97\left(\dfrac{2}{3}+\dfrac{2}{5}\right)-125\cdot\left(\dfrac{3}{5}+\dfrac{1}{3}\right)\right|\)

\(=\left|194\cdot\dfrac{8}{15}-125\cdot\dfrac{14}{15}\right|\)

\(=\left|\dfrac{-66}{5}\right|=\dfrac{66}{5}\)

\(\left|97\frac{2}{3}-125\frac{3}{5}\right|+97\frac{2}{3}-125\frac{3}{5}\)

\(=\left|-\frac{419}{15}\right|+\left(-\frac{419}{15}\right)\)

\(=\frac{419}{15}+\left(-\frac{419}{15}\right)=0\)

học tốt ~~

26.(-125)-125.(-36)+125.(-10)

=(-3250)-(-4500)+(-1250)

=(-3250)+4500+(-1250)

=1250+(-1250)

=0

Chúc bạn hok tốt!!

Bạn nhớ k cho mik nha!!!

26.(-125)-125.(-36)+125.(-10)

=26.(-125)-(-125).36+(-125).10

=(26-36+10)(-125)

=0.(-125)

=0

chúc bạn học tốt!!!

nhớ k cho mk nha!!!

26.(-125)-125.(-36)+125.(-10)

=26.(-125)-(-125).36+(-125).10

=(26-36+10).(-125)

=0.(-125)

=0

⇔-125+x+125=-25

⇔x+(125-125)=-25

⇔x=-25

\(-125+\left(x+125\right)=-25\)

\(-125+x+125=-25\)

\(\left(-125+125\right)+x=-25\)

\(\Rightarrow x=-25\)

-125+(X+125)=-25

X+125=-25+125

X+125=100

X=100-125

X=-25