= ( -25) x 1 +72 x (-25) + (-25) x27

= (- 25) x ( 1 + 72 + 27 )

= (-25) x 100

=-2500 

b 

c 37 x ( 25 + 37 ) - 27 x ( 37 + 25 )

= 37 x 25 + 37 x 37 -27x37 -27x25

= ( 37 x25 -27x25 )+(37x37-27+37)

=25 x ( 37 -27 ) + 37 x (37 - 27)

= 25 x10 + 37x10 

= 250 + 370 

= 770

a) =-25.( 1+72+27)

=-25.100= - 2500

b) = -36.45 + (-36) . 15 - (-36) . 40

= - 36. ( 45+15-40)

= -36 . 20= -720

c) =37.62 - 27 .62

= 62. ( 37 - 27 )

= 62 . 10 

= 620

a: \(=13\cdot55-13\cdot29-55\cdot13+55\cdot29\)

\(=-13\cdot29+55\cdot29=29\cdot42=1218\)

b: \(=37\cdot27+37\cdot25-27\cdot37-27\cdot25\)

\(=27\cdot12=324\)

c: \(=-25\left(28+72\right)=-25\cdot100=-2500\)

-28 . 25 + 75 . ( -25 )

= -700 + ( - 1875 )

= -2575

37 . (27 + 25) - 27. (37 + 35)

= 999 + 925 . 999 - 945

= 925 + ( -945 ) 

= -20

Có cách nhanh hơn

-28x25+72x(-25)=(-28)x25+(-72)x25

=25x[(-28)+(-72)]=25x(-100) =(-2500)

37(27+25)-27(37+35)=0

k minh nha

xin lỗi câu hai minh làm sai.Tại minh quên

a: \(=37\cdot25+37\cdot27-27\cdot37-27\cdot25\)

\(=37\cdot25-27\cdot25=25\cdot10=250\)

b: \(=5\cdot\left(-13\right)-26\cdot8+21\cdot13\)

\(=13\left(-5+21\right)-13\cdot16\)

=13x16-13x16=0

c: =250x34-25x68

=125x68-25x68

=68x100=6800

a: 49x^2-25=0

=>(7x-5)(7x+5)=0

=>7x-5=0 hoặc 7x+5=0

=>x=5/7 hoặc x=-5/7

b: Đề thiếu vế phải rồi bạn

c: (3x-2)^2-9(x+4)(x-4)=2

=>9x^2-12x+4-9(x^2-16)=2

=>9x^2-12x+4-9x^2+144=2

=>-12x+148=2

=>-12x=-146

=>x=146/12=73/6

d: x^3-6x^2+12x-8=0

=>(x-2)^3=0

=>x-2=0

=>x=2

e: x^3-9x^2+27x-27=0

=>(x-3)^3=0

=>x-3=0

=>x=3

a) \(-25+49x^2=0\)

\(\Leftrightarrow49x^2-25=0\)

\(\Leftrightarrow\left(7x\right)^2-5^2=0\)

\(\Leftrightarrow\left(7x-5\right)\left(7x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}7x-5=0\\7x+5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}7x=5\\7x=-5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{7}\\x=-\dfrac{5}{7}\end{matrix}\right.\)

b) \(16x^2-25\left(x-2\right)^2=0\)

\(\Leftrightarrow\left(4x\right)^2-\left[5\left(x-2\right)\right]^2=0\)

\(\Leftrightarrow\left(4x-5x+10\right)\left(4x+5x-10\right)=0\)

\(\Leftrightarrow\left(10-x\right)\left(9x-10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}10-x=0\\9x=10\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=\dfrac{10}{9}\end{matrix}\right.\)

c) \(\left(3x-2\right)^2-9\left(x+4\right)\left(x+4\right)=2\)

\(\Leftrightarrow9x^2-12x+4-9\left(x^2+8x+16\right)=2\)

\(\Leftrightarrow9x^2-12x+4-9x^2-72x-144=2\)

\(\Leftrightarrow-84x-140=2\)

\(\Leftrightarrow-84x=142\)

\(\Leftrightarrow x=-\dfrac{142}{84}\)

\(\Leftrightarrow x=-\dfrac{71}{42}\)

d) \(x^3-6x^2+12x-8=0\)

\(\Leftrightarrow x^3-3\cdot2\cdot x^2+3\cdot2^2\cdot x-2^3=0\)

\(\Leftrightarrow\left(x-2\right)^3=0\)

\(\Leftrightarrow x-2=0\)

\(\Leftrightarrow x=2\)

e) \(-27+27x-9x^2+x^3=0\)

\(\Leftrightarrow x^3-9x^2+27x-27=0\)

\(\Leftrightarrow\left(x-3\right)^3=0\)

\(\Leftrightarrow x-3=0\)

\(\Leftrightarrow x=3\)

Mình sửa lại câu c một chút nha:

c: (3x-2)^2-9(x+4)(x+4)=2

=>(3x-2)^2-9(x+4)^2=2

=>(3x-2)^2-(3x+12)^2=2

=>(3x-2-3x-12)(3x-2+3x+12)=2

=>-14*(6x+10)=2

=>6x+10=-1/7

=>6x=-71/7

=>x=-71/42

-48

\(25+37-48-25-27\)

\(=\left(25-25\right)+\left(37-27\right)+\left(-48\right)\)

\(=0+10+\left(-48\right)\)

\(=-38\)

\(#wee\)

=-48