\(2018^0\left\{15^2:\left[175+2^3.5^2\right]\right\}\\ =1\left\{225:\left[175+8.25\right]\right\}\\ =225:\left[175+200\right]\\ =225:375\\ =\dfrac{3}{5}\)

a: \(65\cdot48+35\cdot48+12\cdot58-12\cdot38\)

\(=48\left(65+35\right)+12\left(58-38\right)\)

\(=48\cdot100+12\cdot20\)

\(=4800+240=5040\)

b: \(2018^2+\left\{15^2:\left[175-\left(2^3\cdot5^2-6\cdot25\right)\right]\right\}\)

\(=1+\left\{\dfrac{225}{175-\left(8\cdot25-150\right)}\right\}\)

\(=1+\dfrac{225}{175-\left(200-150\right)}\)

\(=1+\dfrac{225}{175-50}=1+\dfrac{225}{125}=1+\dfrac{5}{3}=\dfrac{8}{3}\)

a. 5.x + 105 = 200
=> 5x            = 95
=>   x             = 95/5 
=>   x             = 19
Vậy x = 19
b. 15×3 chia hết cho 9
Ta có 15 x 3 = 45
Mà 45 chia hết cho 9 
Nên 15×3 chia hết cho 9
c. x = |2018| – 20180 – |-2016|
       = 2018 - 20180 - 2016
       = -20178
 Vậy x = -20178

a) 5.x + 105 = 200

    5.x           = 200 - 105

    5.x           = 95

      x            = 95 : 5

     x             = 19

\(=-\dfrac{8}{5}\left|-\dfrac{3}{4}\right|+1=-\dfrac{8}{5}\cdot\dfrac{3}{4}+1=-\dfrac{6}{5}+1=-\dfrac{1}{5}\)

a,  15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0

= 15.{32:[1+15]+3}–1

= 15.5–1

= 74

b,  25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }

= 25.{128:[8+4.2]–16}

= 25.24

= 600

c,  2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }

= 2019.{101–1000:[(32+125–36):11–1]}

= 2019.{101–1000:[121:11–1]}

= 2019.{101–1000:10}

= 2019.1

= 2019

\(\frac{51.52....100}{2^{50}}=\frac{\left(51.52....100\right)\left(1.2.3...50\right)}{2^{50}.\left(1.2.3...50\right)}=\frac{1.2.3....100}{\left(1.2\right)\left(2.2\right).\left(2.3\right)...\left(2.50\right)}=\frac{1.2.3...100}{2.4.6...100}=1.3...99\) (đpcm)

P/s: . là dấu nhân

x - (40 - 67) = 2018⁰

x - (-27) = 1

x + 27 = 1

x = 1 - 27

x = -26

\(x\) - (40 - 67) = 2018⁰

\(x\) + (67 - 40) = 1

\(x\) + 27 = 1

\(x\)          = 1 - 27

\(x\)          = - 26 

28²⁰¹⁸:7²⁰¹⁸:2018⁰=(28:7)²⁰¹⁸:1=4²⁰¹⁸:1=4²⁰¹⁸