ai trl đúng cho 3 tick luôn nhé
a)
\(\dfrac{1}{1789}+\dfrac{357}{4680}-\dfrac{18}{3}:\dfrac{408}{45}x\dfrac{99}{1589}=\)
\(\dfrac{1234567}{1234567}-\dfrac{4567}{345678}=\)
không cần làm cách thuận tiện nhé!
Gi úp mik đ i ma `
tính bằng cách thuận tiện nhất a, \(\dfrac{5}{13}\)x\(\dfrac{4}{15}\)x13= b, (\(\dfrac{3}{7}\)+\(\dfrac{5}{2}\))x\(\dfrac{7}{5}\)= c, \(\dfrac{1}{5}\)x\(\dfrac{11}{18}\)+\(\dfrac{11}{18}\)x\(\dfrac{3}{5}\)=
\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{5\times4\times13}{13\times5\times3}=\dfrac{4}{3}\\ b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\dfrac{3}{7}\times\dfrac{7}{5}+\dfrac{5}{2}\times\dfrac{7}{5}=\dfrac{3}{5}+\dfrac{7}{2}=\dfrac{6}{10}+\dfrac{35}{10}=\dfrac{41}{10}\\ c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)
\(\dfrac{2}{5}-(\dfrac{5}{7}-x)=\dfrac{3}{5}\)
Cho mình cách làm luôn nhé!
\(\Rightarrow\dfrac{5}{7}-x=-\dfrac{1}{5}\Rightarrow x=\dfrac{32}{35}\)
\(\dfrac{6}{7}+\dfrac{5}{8}=\)
\(\dfrac{36}{12}-\dfrac{5}{3}=\)
GHI RÕ CÁCH LÀM. AI ĐÚNG MIK TICK CHO
\(\dfrac{6}{7}+\dfrac{5}{8}=\dfrac{48}{56}+\dfrac{35}{56}=\dfrac{83}{56}\)
\(\dfrac{36}{12}-\dfrac{5}{3}=\dfrac{9}{3}-\dfrac{5}{3}=\dfrac{4}{3}\)
\(\dfrac{6}{7}+\dfrac{5}{8}=\dfrac{48}{56}+\dfrac{35}{56}=\dfrac{83}{56}\\\dfrac{36}{12}+\dfrac{5}{3}=\dfrac{36}{12}+\dfrac{20}{12} =\dfrac{56}{12}=\dfrac{14}{3}\)
6/7 + 5/8 = 48/56 + 35/56 = 83/56
36/12 - 5/3 = 36/12 - 20/12 = 16/12 = 4/3
a) \(\dfrac{3}{7}\)+\(\dfrac{4}{9}\)+\(\dfrac{8}{14}\)+\(\dfrac{10}{18}\)
b) \(\dfrac{1}{2}\)x\(\dfrac{2}{3}\):\(\dfrac{5}{6}\)x\(\dfrac{5}{6}\)
bài này là bài tính bằng cách thuận tiện nhất nha !
Giúp mk với
Câu 1:
Cho A = \(\dfrac{1}{\dfrac{99}{\dfrac{1}{2}+}}+\dfrac{2}{\dfrac{98}{\dfrac{1}{3}+}}+\dfrac{3}{\dfrac{97}{\dfrac{1}{4}+....}}+...+\dfrac{99}{\dfrac{1}{\dfrac{1}{100}}}\).
B =\(\dfrac{92}{\dfrac{1}{45}+}-\dfrac{1}{\dfrac{9}{\dfrac{1}{50}+}}-\dfrac{2}{\dfrac{10}{\dfrac{1}{55}+}}-\dfrac{3}{\dfrac{11}{\dfrac{1}{60}+....}}-...\dfrac{92}{\dfrac{100}{\dfrac{1}{500}}}\). Tính \(\dfrac{A}{B}\)
Tính bằng cách thuận tiện nhất:
a) \(\dfrac{7}{11}+\dfrac{3}{4}+\dfrac{4}{11}+\dfrac{1}{4}\); b) \(\dfrac{72}{99}-\dfrac{28}{99}-\dfrac{14}{99}\);
c) \(69,78+35,97+30,22\); d) \(83,45-30,98-42,47\)
a) \(\dfrac{7}{11}+\dfrac{3}{4}+\dfrac{4}{11}+\dfrac{1}{4}=\left(\dfrac{7}{11}+\dfrac{4}{11}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=1+1=2\)
b) \(\dfrac{72}{99}-\dfrac{28}{99}-\dfrac{14}{99}=\dfrac{72-28-14}{99}=\dfrac{30}{99}=\dfrac{10}{33}\)
c) \(69.78+35.97+30.22=\left(69.78+30.22\right)+35.97=100+35.97=135.97\)
Mik đang cần gấp ,nhờ các bạn ,các anh chị giải hộ mik bài này nhé ,ai làm xong mik sẽ tick nhé ạ: X + \(\dfrac{1}{5}\)- \(\dfrac{3}{7}\)= \(\dfrac{6}{35}\)
\(x+\dfrac{1}{5}-\dfrac{3}{7}=\dfrac{6}{35}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{3}{7}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{15}{35}\)
\(x+\dfrac{1}{5}=\dfrac{21}{35}\)
\(x=\dfrac{21}{35}-\dfrac{1}{5}\)
\(x=\dfrac{21}{35}-\dfrac{7}{35}\)
\(x=\dfrac{14}{35}=\dfrac{2}{5}\)
\(x\) + \(\dfrac{1}{5}\) - \(\dfrac{3}{7}\) = \(\dfrac{6}{35}\)
\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{6}{35}\) + \(\dfrac{3}{7}\)
\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) - \(\dfrac{1}{5}\)
\(x\) =\(\dfrac{2}{5}\)
Con cảm ơn cô Hoài, cảm ơn bạn Komuro nhé
Tính bằng cách thuận tiện nhất
\(\dfrac{13}{18}\) x \(\dfrac{9}{26}\) x \(\dfrac{2}{3}\) =
\(\dfrac{44}{15}\) x \(\dfrac{5}{22}\) x \(\dfrac{3}{2}\) =
a: =13/26*9/18*2/3=2/3*1/4=2/12=1/6
b: =44/22*5/15*3/2=2*1/3*3/2=2*1/2=1
\(\dfrac{1}{2}\) x \(\dfrac{45}{33}\) x \(\dfrac{1}{9}\) x \(\dfrac{11}{6}\)
làm chi tiết ra cho mình nhé
nhanh lên mình cần gấp