a.2/3+2/6+2/12+2/24+2/48+2/96+2/192
cứu tui
a-2/3-2/6+2/12+2/24+2/48+2/96+2/192
giúp mjk nkaa:))
`a)-2/3-2/6+2/12+2/24+2/48+2/96+2/192`
`=-4/6-2/6+1/6+1/12+1/24+1/48+1/96`
`=-5/6+1/12+1/24+1/48+1/96`
`=-10/12+1/12+1/24+1/48+1/96`
`=-9/12+1/24+1/48+1/96`
`=-18/24+1/24+1/48+1/96`
`=-17/24+1/48+1/96`
`=-34/48+1/48+1/96`
`=-33/48+1/96`
`=-66/96+1/96=-65/96`
2/3+2/6+2/12+2/24+2/48+2/96+2/192
127/96 nhé
nếu sai bạn sửa cho mình nhé
thank you
mình cảm ơn trước
2/3+2/6+2/12+2/24+2/48+2/96+2/192
\(\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{48}+\dfrac{2}{96}+\dfrac{2}{192}\\ =1+\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{2}{192}\\ =\dfrac{5}{4}+\dfrac{7}{96}=\dfrac{127}{96}\)
2/3+2/6+2/12+2/24+2/48+2/96+2/192=?
2/3+2/6+2/12+2/24+2/48+2/96+2/192
\(\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{48}+\dfrac{2}{96}+\dfrac{2}{192}\)
= \(2\left(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{24}+\dfrac{1}{48}+\dfrac{1}{96}+\dfrac{1}{192}\right)\)
= \(2\left(\dfrac{1}{1.3}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.6}+\dfrac{1}{6.8}+\dfrac{1}{8.12}+\dfrac{1}{12.16}\right)\)
= \(\dfrac{2}{3}+2\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+2\left(\dfrac{2}{4.6}+\dfrac{2}{6.8}\right):2+\dfrac{1}{2}\left(\dfrac{4}{8.12}+\dfrac{4}{12.16}\right)\)
= \(\dfrac{2}{3}+\dfrac{1}{2}+\dfrac{1}{8}+\dfrac{1}{32}\)
= \(\dfrac{127}{96}\)
2/3+2/6+2/12+2/24+2/48+2/96+2/192
2/3 + 2/6 + 2/12 + 2 /24 + 2/48 + 2/96 + 2/192
Đặt BT trên là A
\(2A=\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}\)
\(A=2A-A=\frac{4}{3}-\frac{2}{192}=\frac{127}{192}\)
C=2/3+2/6+2/12+2/24+2/48+2/96+2/192
2/3 + 2/6 + 2/12 + 2/24 + 2/48 + 2/96 + 2/192 =