Bài 1: Thực hiện phép tinh (nhanh nếu có thể):
1, 3^2.18+72.4^2-41.18=
2, (5.4^11-3.16^5):4^10=
3, 7256.4375-725/3650+4375.7255=
4, |347|+(-40)+3150-|-307|=
Bài 2: Tìm x:
a, 17+x-(352+400)=-32
b, -121-x-(35+x)=50
c, (3x-4).(x-1)^3=0
có thể viết rõ hơn ko mình ko hiểu
bài 1: thực hiện phép tính: (tính nhanh nếu có thể)
a,347.2^2.9(216+184):8
b,132-Ơ116-(132-128)^2}
c,16:{400:[200-(37+46.3)]}
d,{184:[96-124:31]-2}.3651
e,46-[(16+71.4):15]-2
f,3^3.18+72.4^2-41.18
g,(56.46-25.23):23
h,(28.54+56.36):21:2
i,(76.34-19.64):(38.9)
k,(2+4+6+...+100).(36.333-108.111)
m,(5.4^11-3.16^5):4^10
n,7256.4375-725
______________
3650+4375.7255
a: \(=347\cdot4\cdot9\cdot400:8=347\cdot36\cdot50=624600\)
c: \(=16:\left\{400:\left[200-37-138\right]\right\}\)
\(=16:\left\{400:25\right\}=16:16=1\)
e: \(=46-\left[300:15\right]-2=46-20-2=24\)
a)\(\left(5.4^{11}-3.16^5\right):4^{10}\)
b)\(\dfrac{7256.4375-725}{3650+4375.7255}\)
c)100+98+96+...+4+2-97-95-...-3-1
giúp mình nhé
\(100 + 98 + 96 + ... + 2 - 97 - 95 - ... -1\)
\(= 100 + (98 - 97) + (96-95) +... + (2 - 1)\)
\(= 100 + 1 + 1 + 1 + ... +1\)
\(=100+1\cdot49\)
\(= 100 + 49 \)
\(= 149\)
1) 33.18+72.42 - 41.18
2) (56.46 - 25.23 ) : 23
3) (76 . 34 - 19 .64 ) : (38.9)
4) (5.411 - 3. 165 ) : 410
5) ( 28.54 + 56.36 ) :21:2
Tính nhanh nếu có thể
1)
33 . 18 + 72 . 42 - 41 . 18
= 33 . 18 + 18 . 43 - 41 . 18
= 18 . ( 33 + 43 - 41 )
= 18 . 50
= 900
2) ( 56 . 46 - 25 . 23 ) : 23
= ( 112 . 23 - 25 . 23 ) : 23
= ( 112 - 25 ) . 23 : 23
= 87 . 23 : 23
= 87
3) ( 76 . 34 - 19 . 64 ) : ( 38 . 9 )
= ( 19 . 136 - 19 . 64 ) : ( 19 . 18 )
= 19 . ( 136 - 64 ) : ( 19 . 18 )
= 19 . 72 : 19 . 18
= 19 . 4
= 76
4) ( 5 . 411 - 3 . 165 ) : 410
= ( 5 . 411 - 3 . 410 ) : 410
= ( 20 . 410 - 3 . 410 ) : 410
= ( 20 - 3 ) . 410 : 410
= 17
\(\frac{7256.4375-725}{3650+4375.7255}\)
\(\frac{3^{10}.11+3^{10}.5;}{3^9.2^4}\)\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(\left(125^3.7^5-175^5.5\right):2001^{2002}\)
\(\frac{7256.4375-725}{4375.7255+3650}=\frac{\left(7255+1\right).4375-725}{4375.7255+3650}=\frac{7255.4375+4375-725}{7255.4375+3650}=\frac{7255.4375+3650}{7255.4375+3650}=1\)
\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3.16}{16}=3\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^2.78}{26.2^2}=\frac{78}{26}=3\)
\(\left(125^3.7^5-175^5.5\right):2001^{2002}\) ( bạn xem lại đề xem sai đâu ko nhé )
Để Thiên giải câu 3 cho:
(1253.75 -1755;5):20012001
\(=\left[\left(5^3\right)^3.7^5-175^5:5\right]:2001^{2002}\)
\(=\left(5^9.7^5-175:5\right):2001^{2002}\)
\(=\left(5^5.5^4.7^4.7-175^4.175:5\right):2001^{2002}\)
\(=\left(5^5.35^4.7-175^4.35\right):2001^{2002}\)
\(=\left(5^4.35^4.5.7-175^4.35\right):2001^{2002}\)
\(=\left(175^4.35-175^4.35\right):2001^{2002}\)
\(=0:2001^{2002}\)
\(=0\)
Thực hiện phép tính:
7256.4375-725/3650+4375.7255.
Làm xong kb vs mình nha. Dấu chấm là dấu nhân nha.
\(\dfrac{7256.4375-725}{3650+4375.7255}\)
tính nhanh
Ta có:
\( \dfrac{7256.4375-725}{3650+4375.7255}\\ =\dfrac{7255.4375+4375-7255}{3650+4375.7255}\\ =\dfrac{7255.4375+\left(4375-725\right)}{3650+4375.7255}\\ =\dfrac{7255.4375+3650}{3650+4375.7255}\\ =1\)
Vậy giá trị của \(\dfrac{7256.4375-725}{3650+4375.7255}=1\)
7256.4375-725=(7255+1).4375-725=7255.4375+4375-725=7255.4375+3650
⇒(7256.4375−725)/(3650+4375.7255)=(7255.4375+3650)/(3650+4375.7255)=1
7256.4375-725/3650+4375.7255
Ta có: \(7256.4375-\dfrac{725}{3650}+4375.7255\)
\(=7256.4375+4375.7255-\dfrac{29}{146}\)
\(=4375\left(7256-7255\right)-\dfrac{29}{146}\)
\(=4375.1-\dfrac{29}{146}\)
\(=\dfrac{638750}{126}-\dfrac{29}{126}\)
\(=\dfrac{638721}{126}=\dfrac{70969}{14}\)
Chúc bn học tốt!!!
1/ 33.18+72.42-41.18 4/ (2+4+6+......+100).(36.333-108.111)
2/ (56.46-25.23):23 5/ (5.411-3.165):410
3/ (28.54+56.36):21:2
3^3.18+72.4^2-41.18=27.18+18.64-41.18=18(27+64-41)=18.50=900
(56.46-25.23);23=(112.23-25.23):23=87.23:23=87
(28.54+56.36):21:2=(28.54+28.72):21:2=28.126:21:2=(28:2).(126:21)=14.6=84
(2+4+6+....+100)(36.333-108.111)=(2+4+6+100)(108.111-108.111)=0
(5.4^11-3.16^5):4^10=(5.4^11-3.4^10):4^10=5.4-3=17