Vì \(\frac{312}{216}>1\) mà\(\frac{126}{132}< 1\)

=> \(\frac{312}{216}>\frac{126}{132}\)

 ta co : 312/216=312x11/216x11=3432/2376

126/132=126x18/132x18=2268/2376

vi 3434>2268 suy ra 3434/2376>2268/2376

suy ra 312/216>126/132

vay.......

Ta thấy : 

\(\frac{312}{216}>1\)mà \(\frac{126}{132}< 1\)

Nên \(\frac{312}{216}>\frac{126}{132}\)

~ Chúc bạn học giỏi ! ~

Ta có: \(\dfrac{312}{x}-\dfrac{312}{x+4}=\dfrac{1}{2}\)

\(\Leftrightarrow x\left(x+4\right)=624x+2496-624x\)

\(\Leftrightarrow x^2+4x-2496=0\)

\(\Leftrightarrow\left(x+2\right)^2=2500\)

\(\Leftrightarrow\left[{}\begin{matrix}x=48\\x=-52\end{matrix}\right.\)

=-45*312-312+312*(-54)

=312(-45-1-54)

=-31200

312 * 425 + 312 * 574 + 312

= 312 x ( 425 + 574 + 1 )

= 312 x 1000

= 312000

k mik nha

=312 x 425 + 312 x 574 + 312 x 1

= 312 x ( 425 + 574 + 1 )

= 312 x 1000 = 312000

312 x 425 + 312 x 574 + 312

= 312 x 425 + 312 x 574 + 312 x 1

= 312 x ( 425 + 574 + 1 )

= 312 x 1000

= 312000

=312x425+312x574+312x1

=312x(425+574+1)

=312x1000

=312000

\(312\times425+312\times574+312\)

\(=312\times\left(425+574+1\right)\)

\(=312\times1000\)

\(=312000\)

312 × 425 + 312 × 574 + 312

= 312 × (425 + 574 + 1)

= 312 × 1000

= 312000

312x425+312x574+312x1

=312x(425+574+1)

=312x1000

=3120000

A=[(38+17)+125]+29

A=175+29

A=204

B=312.3

B=936

C=1+1+1+1+1

C=5

D=(125:5).(36:9)

D=25.4

D=100

12.34<mx2<3.45+312:26

12.34<mx2<3.45+12

12.34<mx2<15.45

12.34:2<m<15.45:2

6.17<m<7.725

m = tu tinh