a) \(2^{135}=2^{3.45}=\left(2^3\right)^{45}=8^{45}\)
\(3^{90}=3^{2.45}=\left(3^2\right)^{45}=9^{45}\)
Vì \(8^{45}< 9^{45}\)nên \(2^{135}< 3^{90}\)

b) \(4^{75}=4^{3.25}=\left(4^3\right)^{25}=64^{25}\)
\(3^{100}=3^{4.25}=\left(3^4\right)^{25}=81^{25}\)
Vì \(64^{25}< 81^{25}\)nên \(4^{75}< 3^{100}\)

c) \(4^{100}=4^{4.25}=\left(4^4\right)^{25}=256^{25}\)
\(9^{75}=9^{3.25}=\left(9^3\right)^{25}=729^{25}\)
Vì \(256^{25}< 729^{25}\)nên \(^{4^{100}< 9^{75}}\)

\(2^{100}=\left(2^4\right)^{25}=16^{25};3^{75}=\left(3^3\right)^{25}=27^{25}\)

\(\Leftrightarrow2^{100}

\(5^{200}=\left(5^2\right)^{100}=25^{100}\)

\(3< 25=>3^{100}< 25^{100}=>3^{100}< 5^{200}\)

\(\frac{75^{20}}{45^{10}.25^{15}}=\frac{25^{20}.3^{20}}{3^{10}.3^{10}.5^{10}.25^{15}}=\frac{25^{20}}{25^5.25^{15}}=1\)

\(=>75^{20}=45^{10}.25^{15}\left(dpcm\right)\)

P/S:nếu a=b=>a:b=1 mk làm theo cách đó cho nhanh mà bn ghi sai đề r

\(a=2^{100}=\left(2^4\right)^{25}=16^{25}\)

\(b=3^{75}=\left(3^3\right)^{25}=27^{25}\)

\(c=5^{50}=\left(5^2\right)^{25}=25^{25}\)

Vì \(16^{25}< 25^{25}< 27^{25}\)

\(\Rightarrow a< c< b\)

\(a=2^{100},b=3^{75},c=5^{50}\\ \Rightarrow a=30^{85},b=30^{65},c=30^{44}\\ \Rightarrow a>b>c\)

Ta có:

\(a=2^{100}=2^{4\cdot25}=\left(2^4\right)^{25}=16^{25}\)

\(b=3^{75}=3^{3\cdot25}=\left(3^3\right)^{25}=27^{25}\)

\(c=5^{50}=5^{2\cdot25}=\left(5^2\right)^{25}=25^{50}\)

Ta thấy: 

\(16< 25< 27\)

\(\Rightarrow16^{25}< 25^{25}< 27^{25}\)

\(\Rightarrow2^{100}< 5^{50}< 3^{75}\)

\(\Rightarrow a< c< b\)

a, 24^10 < 3^30 + 4^30 + 5^30

b, 2^100 < 5^50 < 3^75.

ta có:\(\frac{75}{100}=\frac{3}{4}=\frac{3.5}{4.5}=\frac{15}{20};\frac{4}{5}=\frac{4.4}{4.5}=\frac{16}{20}\)

=>\(\frac{75}{100}

\(\frac{75}{100}=\frac{3}{4}

Ta có :

\(2^{100}=\left(2^4\right)^{25}=16^{25}\)

\(3^{75}=\left(3^3\right)^{25}=27^{25}\)

\(5^{50}=\left(5^2\right)^{25}=25^{25}\)

Do \(16^{25}< 25^{25}< 27^{25}\)

\(\Rightarrow2^{100}< 5^{50}< 3^{75}\)