`#040911`

`(x + 5)^3 = (2x)^3`

`\Rightarrow x + 5 = 2x`

`\Rightarrow x + 5 - 2x = 0`

`\Rightarrow 5 + (x - 2x) = 0`

`\Rightarrow 5 - x = 0`

`\Rightarrow x = 5 - 0`

`\Rightarrow x = 5`

Vậy, `x= 5.`

Cảm ơn bạn nha

a) 1 + 3 + 5 + ... + 13

= (13 + 1).[(13 - 1) : 2 + 1] : 2

= 14 . 7 : 2

= 49

= 7²

b) 3² + 4² + 12²

= 9 + 16 + 144

= 169

= 13²

Ta có \(3.5^{2x}-4=5^x.5^x-4\Rightarrow3.5^{2x}=5^{2x}\Rightarrow3.5^{2x}-5^{2x}=0\Rightarrow2.5^{2x}=0.\)

Vì \(5^{2x}\ge1\Rightarrow2.5^{2x}\ge2\Rightarrow\)

Không có giá trị x thỏa mãn.

bài toán này ko có giá trị thõa mãn

53−3(x+4)=32

\(^{3^2}\).\(^{3^3}\)+\(2^3\).\(2^2\)

(\(^{2^3}\).\(^{3^3}\))+(\(2^2\).​\(^{3^2}\)​​​

=275

\(\left(\dfrac{1}{4}\right)^{2n}=\left(\dfrac{1}{8}\right)^2\)

\(\Rightarrow\left(\dfrac{1}{2}\right)^{2.2n}=\left(\dfrac{1}{2}\right)^{3.2}\)

\(\Rightarrow\left(\dfrac{1}{2}\right)^{4n}=\left(\dfrac{1}{2}\right)^6\)

\(\Rightarrow4n=6\)

\(\Rightarrow n=\dfrac{6}{4}=\dfrac{3}{2}\)

n = 3/2

1/2 mũ n = 1/2 mũ 6

Vậy x = 6

\(\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{8}\right)^2\)

\(=>\left(\dfrac{1}{2}\right)^n=\left[\left(\dfrac{1}{2}\right)^3\right]^2\)

\(=>\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{2}\right)^6\)

\(\Rightarrow n=6\)

\(\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{8}\right)^2 \Rightarrow\left(\dfrac{1}{2}\right)^n=\dfrac{1}{64} \Rightarrow\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{2}\right)^6\Rightarrow n=6\)

mũ 2.

2^x.2=8
2^x   =8:2
2^x   =4
2^x   =2^2
=>x  =2

2^x.2=8

=>2^x=4

=>2^x=2²

=>x=2