ta có 2x-5+16=15-5x+3 => 7x=7=>x=1

(x-2)(x+5)-18=x^2-4x => x^2+3x-10-18=x^2-4x =>7x=28 =>x=4

a: =>3[(2x-1)^2-4]=49*125:175+196=231

=>(2x-1)^2-4=77

=>(2x-1)^2=81

=>2x-1=9 hoặc 2x-1=-9

=>x=5 hoặc x=-4

b: \(\Leftrightarrow2\cdot3^x\cdot3-4^3=7^2\cdot\left(27-25\right)\)

=>\(6\cdot3^x=49\cdot2+64=162\)

=>3^x=27

=>x=3

Lời giải:
a.

$3[(2x-1)^2-4]-14^2=7^2.5^3:175=35$

$3[(2x-1)^2-4]=35+14^2=231$

$(2x-1)^2-4=231:3=77$

$(2x-1)^2=77+4=81=9^2=(-9)^2$

$\Rightarrow 2x-1=9$ hoặc $2x-1=-9$

$\Rightarrow x=5$ hoặc $x=-4$

b.

$2.3^{x+1}-4^{10}:4^7=(7^5:7^3).(3^3-5^2)=7^2.2=98$

$2.3^{x+1}-4^3=98$

$2.3^{x+1}=98+4^3=162$

$3^{x+1}=162:2=81=3^4$

$\Rightarrow x+1=4$

$\Rightarrow x=3$

a) \(\left[\left(x+32\right)-17\right].2=42\)

\(\left[\left(x+32\right)-17\right]=42:2\)

\(\left[\left(x+32\right)-17\right]=21\)

\(\left(x+32\right)=21+17\)

\(\left(x+32\right)=38\)

\(x=38-32\)

\(x=6\)

b) \(125+\left(145-x\right)=175\)

\(\left(145-x\right)=175-125\)

\(\left(145-x\right)=50\)

\(x=145-50\)

\(x=95\)

Answer:

Bài 3:

\(334-\left(-75\right)+[\left(-175\right)-34]\)

\(=334+75-175-34\)

\(=\left(334-34\right)+\left(75-175\right)\)

\(=300+\left(-100\right)\)

\(=200\)

\(68-\left(-45\right)-[368-\left(-145\right)]\)

\(=68+45-[368+145]\)

\(=\left(68-368\right)+\left(45-145\right)\)

\(=\left(-300\right)+\left(-100\right)\)

\(=-400\)

Bài 4:

\(-17-\left(x-5\right)=-52\)

\(\Rightarrow x-5=-17-\left(-52\right)\)

\(\Rightarrow x-5=35\)

\(\Rightarrow x=40\)

\(3\left(7-x\right)+\left(-12\right)=-75\)

\(\Rightarrow3\left(7-x\right)=-75-\left(-12\right)\)

\(\Rightarrow3\left(7-x\right)=-63\)

\(\Rightarrow7-x=-21\)

\(\Rightarrow x=28\)

\(H\left(x\right)=\left(x-3\right)\left(x^2+5\right)\)

\(\Rightarrow H\left(x\right)=x^3+5x-3x^2-15\)

Dây nha bạn

a) (x - 25) - 130 = 150

=> x - 25            = 150 + 130

=> x - 25            = 280

=> x                   = 280 + 25

=> x                   = 305

c) 435 + 5.x = 135

=>          5.x = 135 - 435

=>          5.x = - 300

=>             x = -300 : 5

=>             x = - 60

\(\left(x-25\right)-130=150\)

\(\left(x-25\right)=150+130\)

\(\left(x-25\right)=280\)

\(x=280+25\)

\(x=305\)

a. (x - 25) - 130 = 150

               x - 25  = 280

               x         = 305

b. 125 + (145 - x) = 175

                145 - x  = 50

                          x  = 95

c. 435 + 5x = 135

              5x = -300

                x = -60

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