1.<,>,= ?

256 x 6.....512 x 3

512 x 3.....256 x 6

999 x 2.....1000

512 x 5.....1024

1024.....512 x 5

1024.....512 x 2

512.....256 x 2

256.....128 x 2

128.....64 x 2

64.....32 x 2

32.....16 x 2

Tìm x : 512+3.(2^3+2^2 x )=572

Bai 1: Rut gon bieu thuc sau 

B=(2/3)^3×(-3/4)^4×(-1)^5/(2/5)^2 × (-5/12)^3

Bai 2: Tim ia tri bieu thuc sau

M= 512- 512/2- 512/2^2- 512/2^2 - 512/2^3...512/2^10

512 -512/2 -512/2^2 -512/2^3 -512/2^4-512/2^5-512/2^6-512/2^7-512/2^8-512/2^9-512/2^10

Tìm x

a) 15+3.(120-2.x)=316

b) 512+3.(2^3-2^2.x)=512

hơi khó nên 5 k nha

giải rõ nhanh tay thì còn chậm tay thì mất

Tìm x biết:  512+3 .(2^3 + 2^2 . x)= 572

tính B=512-512/2-512/2^3-512/2^4-...-512/2^10

tính:

\(512-\dfrac{512}{2}-\dfrac{512}{2^2}-\dfrac{512}{2^3}-...-\dfrac{512}{2^{10}}\)