\(\left(3x+2\right)^3=512\\ \Rightarrow\left(3x+2\right)^3=8^3\\ \Rightarrow3x+2=8\\ \Rightarrow3x=8-2\\ \Rightarrow3x=6\\ \Rightarrow x=\dfrac{6}{3}\\ \Rightarrow x=2\)
Vậy `x=2`
\(\left(3x+2\right)^3=512\\ \Rightarrow\left(3x+2\right)^3=8^3\\ \Rightarrow3x+2=8\\ \Rightarrow3x=6\\ \Rightarrow x=2.\)