a, 27³ : 3⁵  =  ( 3³)³ : 3⁵ = 3⁹ : 3⁵ = 3⁴

b, 7² . 343 . 49³⁰ = 7². 7³.(7²)³  = 7¹¹

c, 625 : 5³ = 5⁴ : 5³ =  5

d, 1 000 000 : 10³ = 10⁶ . 10³ = 10³

e, 11⁵ : 121= 11⁵ : 11² = 11³

f, 8⁷ : 64 :8 = 8⁷ : 8² : 8¹ = 8⁴

i, 1024 . 16 : 2⁶  = 2¹⁰ . 2³ : 2⁶ = 2⁷

B2:

 số chính phương là:

4 ; 121 ; 196 ; 225.

Bài 2 :

Số chính phương là :

\(4=2^2\)

\(121=11^2\)

\(196=14^2\)

\(225=25^2\)

( 3/7 ) 5 x ( 7/3 ) - 1 x ( 5/3 )6 : ( 343/652) - 2

= ( 3/7 x 7/3 ) + 5 - 1 x ( 5/3 : 343/652 ) - 2

= 1 + 5 - 1 x 2 - 1715/1956

= 6 - 2 - 1715/1956

=4 - 1715/1956

= 6109/1715

bn ê, đề là j vậy,sao mk đọc mà ko hỉu

ban ghi gi the (3/7)5 nghia la gi

\(\left(\frac{3}{7}\right)^5.\left(\frac{7}{3}\right)^{-1}.\left(\frac{5}{6}\right)^6.\left(\frac{343}{625}\right)^{-2}\)

\(=\left(\frac{3}{7}\right)^5.\left(\frac{3}{7}\right).\left(\frac{5}{2.3}\right)^6.\left(\frac{5^4}{7^3}\right)^2\)

\(=\frac{3^5}{7^5}.\frac{3}{7}.\frac{5^6}{2^6.3^6}.\frac{5^8}{7^6}=\frac{1}{2^6}.\frac{3^6}{3^6}.\frac{5^{14}}{1}.\frac{1}{7^{12}}=\frac{5^{14}}{2^6.7^{12}}\)

Nó đâu có phải là số nguyên đâu

3/7 x 5/6 +5/6 x3/7

= (3/7x5/6) + (5/6x3/7)

= 15/42 + 15/42  = 30/42 = 5/7

a)=32

b)0.04

chắc chắn đúng

125^x . 5^x+1 = 625² . 5

125^x . 5^x . 5 = ( 5⁴ )² . 5

625^x . 5 = 5⁹

625^x = 5⁹ : 5

625^x = 5⁸

5^4x = 5⁸

4x = 8

x = 2

49^x+1 . 7³ = 343² . 49

( 7² )^x+1 . 7³ = ( 7³ )² . 7²

7^2x+5 = 7⁸

2x + 5 = 8

2x = 3

x = 3/2

e tách ra nhé.☘

;))

a) \(\dfrac{49}{81}=\dfrac{7^x}{9^x}\)(sửa đề)

\(\Leftrightarrow\left(\dfrac{7}{9}\right)^2=\left(\dfrac{7}{9}\right)^x\)\(\Rightarrow x=2\)

b) \(\dfrac{-64}{343}=\left(-\dfrac{4^x}{7^x}\right)\)(sửa đề)

\(\Leftrightarrow\left(-\dfrac{4}{7}\right)^3=\left(-\dfrac{4}{7}\right)^x\) \(\Rightarrow x=3\)

c) \(\dfrac{9}{144}=\dfrac{3^x}{12^x}\)(sửa đề)

\(\Leftrightarrow\left(\dfrac{3}{12}\right)^2=\left(\dfrac{3}{12}\right)^x\Rightarrow x=2\)

d) \(-\dfrac{1}{32}=\left(-\dfrac{1^x}{2^x}\right)\)(sửa đề)

\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^5=\left(-\dfrac{1}{2}\right)^x\Rightarrow x=5\)

Mong bạn xem lại đề bài.

a)\(\dfrac{1}{3}^x=\dfrac{1}{729}\)

\(\dfrac{1}{3}^x=\dfrac{1}{3}^6\)

Suy ra x=6

vậy x=6

b)\(\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^x=\dfrac{1}{36}\)

\(\left(-\dfrac{1}{6}\right)^x\)=\(\dfrac{1}{6}^2\)

Do đó x=2

Vậy x=2

c)\(\dfrac{25}{5}^x=\dfrac{1}{125}\)

\(5^x=5^{-3}\)

Suy ra x=-3

Vậy x=-3

d)\(7^{2n-\dfrac{1}{49}}=-343\)

\(-7^{2n-\dfrac{1}{49}}=-7^3\)

Do đó \(2n-\dfrac{1}{49}=3\)

2n=\(\dfrac{148}{49}\)

n=\(\dfrac{74}{49}\)

vậy n=\(\dfrac{74}{49}\)

chúc bạn học tốt ạ

a)\(\left(5x+1\right)^2=\frac{36}{49}\\ \left(5x+1\right)^2=\left(\frac{6}{7}\right)^2\\ \Rightarrow\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=\frac{-6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{-1}{35}\\x=\frac{-13}{35}\end{matrix}\right.\)

vậy...

2.

a) \(\left(5x+1\right)^2=\frac{36}{49}\)

⇒ \(5x+1=\pm\frac{6}{7}\)

⇒ \(\left[{}\begin{matrix}5x+1=\frac{6}{7}\\5x+1=-\frac{6}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}5x=\frac{6}{7}-1=-\frac{1}{7}\\5x=\left(-\frac{6}{7}\right)-1=-\frac{13}{7}\end{matrix}\right.\) ⇒ \(\left[{}\begin{matrix}x=\left(-\frac{1}{7}\right):5\\x=\left(-\frac{13}{7}\right):5\end{matrix}\right.\)

⇒ \(\left[{}\begin{matrix}x=-\frac{1}{35}\\x=-\frac{13}{35}\end{matrix}\right.\)

Vậy \(x\in\left\{-\frac{1}{35};-\frac{13}{35}\right\}.\)

Chúc bạn học tốt!