Tính:
a)\(\frac{{ - 6}}{{18}} + \frac{{18}}{{27}}\);
b)\(2,5 - ( - \frac{6}{9})\);
c) \(- 0,32.( - 0,875)\);
d)\(( - 5).2\frac{1}{5}\)
Những câu hỏi liên quan
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}-\frac{2}{9}=\frac{1}{3}\)
\(\frac{x}{27}=\frac{1}{3}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{5}{9}\)
\(\Rightarrow x\div27=\frac{5}{9}\)
\(\Rightarrow x=\frac{5}{9}\times27\)
\(\Rightarrow x=15\)
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Dễ quá à
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{5}{9}\)
\(\Rightarrow x.9=5.27\)
\(\Rightarrow x.9=135\)
\(\Rightarrow x=15\)
Vậy x=15
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\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{5}{9}\)
\(x=\frac{5}{9}\times27\)
\(x=15\)
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Rút gọn rồi tính
\(\frac{8}{5}\)- \(\frac{18}{27}\)
\(\frac{12}{20}\)-\(\frac{6}{18}\)
\(\frac{8}{24}\)-\(\frac{5}{25}\)
\(\frac{18}{21}\)-\(\frac{12}{27}\)
\(\frac{8}{5}-\frac{18}{27}\)
\(=\frac{8}{5}-\frac{2}{3}\)
\(=\frac{24}{15}-\frac{10}{15}\)
\(=\frac{14}{15}\)
\(\frac{12}{20}-\frac{6}{18}\)
\(=\frac{3}{5}-\frac{1}{3}\)
\(=\frac{9}{15}-\frac{5}{15}\)
\(=\frac{4}{15}\)
\(\frac{8}{24}-\frac{5}{25}\)
\(=\frac{1}{3}-\frac{1}{5}\)
\(=\frac{5}{15}-\frac{3}{15}\)
\(=\frac{2}{15}\)
\(\frac{18}{21}-\frac{12}{27}\)
\(=\frac{6}{7}-\frac{4}{9}\)
\(=\frac{54}{63}-\frac{28}{63}\)
\(=\frac{26}{63}\)
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1)8/5-2/3=14/15
2)3/5-1/3=4/15
3)1/3-1/5=2/15
4)6/7-4/9=26/63
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a) Trong các số sau, những phân số nào biểu diễn số hữu tỉ \(\frac{{ - 5}}{9}\)?
\(\frac{{ - 10}}{{18}};\,\frac{{10}}{{18}};\,\frac{{15}}{{ - 27}};\, - \frac{{20}}{{36}};\,\frac{{ - 25}}{{27}}.\)
b) Tìm số đối của mỗi số sau: \(12;\,\frac{{ 4}}{9};\, - 0,375;\,\frac{0}{5};\,-2\frac{2}{5}.\)
a) Ta có:
\(\begin{array}{l}\frac{{ - 10}}{{18}} =\frac{{ - 10:2}}{{18:2}} = \frac{{ - 5}}{9};\,\,\,\\\frac{{10}}{{18}} = \frac{{10:2}}{{18:2}} =\frac{5}{9};\,\,\\\,\frac{{15}}{{ - 27}} =\frac{{15:(-3)}}{{ - 27:(-3)}} = \frac{{ - 5}}{9};\,\\ - \frac{{20}}{{36}} =- \frac{{20:4}}{{36:4}}= \frac{{ - 5}}{9}.\end{array}\)
Vậy những phân số nào biểu diễn số hữu tỉ \(\frac{{ - 5}}{9}\) là: \(\frac{{ - 10}}{{18}};\,\frac{{15}}{{ - 27}};\, - \frac{{20}}{{36}}.\)
b) Số đối của các số \(12;\,\frac{{ 4}}{9};\, - 0,375;\,\frac{0}{5};\,-2\frac{2}{5}\) lần lượt là: \( - 12;\,\frac{-4}{9};\,0,375;\,\frac{0}{5};\, 2\frac{2}{5}\).
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\(2\frac{1}{8}:1\frac{1}{40}-\left(15-6\frac{13}{18}\right):11\frac{1}{27}\)
\(\frac{13.4^6.\left(28\frac{7}{13}-27\frac{5}{18}\right)}{59.212.\left(\frac{5}{14}+\frac{5}{84}+\frac{5}{204}+\frac{5}{374}\right)}\)
thực hiện phép tính:
a) \(-\sqrt{27}+6\sqrt{\frac{1}{3}}-\sqrt{12}\)
b) \(\sqrt{\frac{72}{9}}:\sqrt{18}-\frac{5}{6}\)
c) \(\frac{2}{3}\sqrt{3}-\frac{1}{4}\sqrt{18}+\frac{2}{5}\sqrt{2}-\frac{1}{4}\sqrt{12}\)
bài 1 : tính
a)\(\frac{-5}{13}-\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)\) b) \(\left(\frac{3}{9}-\frac{9}{18}\right)+\frac{3}{6}-\left(\frac{1}{3}-\frac{1}{2}\right)-\frac{5}{15}\) c) \(\frac{9}{18}+\frac{16}{32}-\frac{12}{46}-\frac{9}{17}\) d) \(\left(\frac{14}{18}+\frac{-16}{27}\right)-\left(\frac{2}{3}-\frac{5}{15}\right)\)
a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)
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\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}+\frac{16}{24}+\frac{2}{3}\)
=\(\frac{1}{3}+\frac{1}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(=\frac{8}{3}\)
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\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
\(=\frac{9}{27}+\frac{8}{24}+\frac{18}{27}+\frac{16}{24}+\frac{2}{3}\)
\(=\frac{1}{3}+\frac{1}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(=\left[\frac{1}{3}+\frac{2}{3}\right]+\left[\frac{1}{3}+\frac{2}{3}\right]+\frac{2}{3}\)
\(=1+1+\frac{2}{3}=2+\frac{2}{3}=\frac{8}{3}\)
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\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)
\(\frac{1}{3}+\frac{1}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(\frac{2}{3}+\frac{2}{3}+\frac{2}{3}+\frac{2}{3}\)
\(\frac{8}{3}\)
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Câu 1: Chứng tỏ rằng:
\(\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{26}+\frac{1}{27}>\frac{8}{27}\)
Câu 2: Tính:
\(D=\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)
#)Giải :
Câu 1 :
Đặt \(A=\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{27}\)
\(\Rightarrow A>\frac{1}{27}+\frac{1}{27}+...+\frac{1}{27}\)( 8 số hạng )
\(\Rightarrow A>\frac{8}{27}=\frac{8}{27}\)
\(\Rightarrow A>\frac{8}{27}\)
#~Will~be~Pens~#
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Câu 1:(trội)
Ta có:\(\frac{1}{20}+\frac{1}{21}+...+\frac{1}{27}>\frac{1}{27}+\frac{1}{27}+...+\frac{1}{27}=\frac{8}{27}\left(đpcm\right)\)
Câu 2:\(D=\frac{2^{25}.3^{15}+3^{15}.5.2^{26}}{2^{25}.3^{17}+3^{15}.2^{25}}=\frac{2^{25}3^{15}\left(1+5.2\right)}{2^{25}3^{15}\left(3^2+1\right)}=\frac{11}{10}\)
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